1. The problem statement, all variables and given/known data A piece of wire slides, without friction, along two similiar wires. The resistance per unit length of all wires is 0.350 ohms/m, and a constant magnetic field, B= 1.90T, points up, perpendicular to the loop. The distance between the parallel, fixed wires is 10.0cm. At the instant the sliding wires moves with velocity , v= 1.3 m/s, the loop length is L= 30.0cm. what is the current in the loop 2. Relevant equations E = -d0 / dt I=E/R 3. The attempt at a solution 0.350 ohms/m B= 1.90 T d = 0.1 m V = 1.3m/s L= 0.3 m E = (1.90T)(0.13m/s) = 0.247V Resistance in loop = (o.3m)90.350ohms/m) = 0.105 ohms E= 2.47x10^-1 V R= 1.05x10^-1 ohms I = 2.47x10^-1 V / 1.05x10^-1 ohms = 2.35A My answer is 2.35 A but was told that there is some change in quantity that I missed? I feel like that answer is correct, can anyone show me where I might have skipped a step or got my units wrong? thanks.