What is the Cutoff Wavelength for a Photon Passing Through a Waveguide?

  • Context: Undergrad 
  • Thread starter Thread starter henxan
  • Start date Start date
  • Tags Tags
    Photon Wave
Click For Summary
SUMMARY

The cutoff wavelength for a photon passing through a rectangular waveguide is defined by the formula λc = 2W, where W is the width of the waveguide. For the TE01 and TE10 modes, wavelengths longer than this cutoff will experience attenuation. Quantum mechanics allows for a non-zero probability of photon traversal even with longer wavelengths, but practical definitions of cutoff depend on acceptable power reduction levels, such as 1% or 0.1% of the original power.

PREREQUISITES
  • Understanding of waveguide theory
  • Familiarity with electromagnetic wave propagation
  • Knowledge of quantum mechanics principles
  • Basic grasp of TE modes in waveguides
NEXT STEPS
  • Study the derivation of the cutoff wavelength in rectangular waveguides
  • Explore the implications of evanescent modes in waveguide design
  • Learn about power transmission efficiency in waveguides
  • Investigate the differences between TE and TM modes in waveguides
USEFUL FOR

Physicists, electrical engineers, and anyone involved in optical or microwave waveguide design and analysis.

henxan
Messages
46
Reaction score
2
Photon through a "wave guide"

Given the attached image.

A photon approaches a "slit/waveguide" of width W. The waveguide has a length D>\lambda...

What is the largest wavelength the photon can have, and still pass through?
 

Attachments

  • photon.png
    photon.png
    1.9 KB · Views: 506
Science news on Phys.org


If you are talking photons, then pretty much any. With quantum mechanics you should find that there would be a non-zero, however incredibly small it would be, probability for the photon to traverse the waveguide. It's all just a question of where you want to specify the cut-off (1%, 0.1%, age of the Universe?).

For classical electromagnetics, it can also be a question of where you want to cutoff. In terms of propagating modes, that is a distinct answer. If you have a rectangular waveguide, then the cutoff wavelength for the lowest mode, assuming a square waveguide, is

\lambda_c = 2W

for the TE_{01} and TE_{10} modes.

But again, if you have a wavelength longer than the cutoff wavelength above, the wave will travel in attenuation. If the length of the waveguide is very short, then you can still get an appreciable amount of power transmitted through. So for the evanescent modes, it is once again just a question of what cutoff you wish to define in terms of the power reduction before you decide that the wave is effectively gone.
 


Thanks for answering! :)..

Yes, that was partially what I was wondering about, the cutoff wavelength :)..
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
828
  • · Replies 2 ·
Replies
2
Views
1K