What is the de Broglie wavelength of this electron?

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SUMMARY

The de Broglie wavelength of an electron with a kinetic energy of 500 eV can be calculated using the formula λ = h/p, where h is Planck's constant and p is the momentum. The kinetic energy is converted to joules as 8.01 x 10^-17 J. To find momentum, the relationship T = p²/(2m) is utilized, allowing for the calculation of momentum from the known mass of the electron. This process leads directly to the determination of the de Broglie wavelength.

PREREQUISITES
  • Understanding of kinetic energy equations
  • Familiarity with Planck's constant (h = 6.626 x 10^-34 J·s)
  • Knowledge of electron mass (approximately 9.11 x 10^-31 kg)
  • Basic grasp of momentum concepts
NEXT STEPS
  • Calculate the momentum of an electron using the kinetic energy formula T = p²/(2m)
  • Research the significance of Planck's constant in quantum mechanics
  • Explore the implications of de Broglie wavelength in wave-particle duality
  • Learn about the applications of de Broglie wavelength in electron microscopy
USEFUL FOR

Students studying quantum mechanics, physics enthusiasts, and anyone interested in the wave-particle duality of electrons.

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Homework Statement


What is the de Broglie wavelength of this electron?
Given is 500 eV


Homework Equations


KE= 1/2 mv^2
1 eV=1.602x19^-19 J


The Attempt at a Solution


I converted the 500 eV to 8.01x10^-17 via the given conversion. Now I'm stuck.
 
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The deBroglie wavelength is given by the relation

\lambda = \frac{h}{p}

where h is the plank constant and p is momentum. I'm assuming the number in eV you were given is the kinetic energy of the electron--you can look up its mass to get it in terms of momentum through

T \text{(kinetic energy)}=\frac{p^2}{2m}

Can you figure how to get the wavelength of it from this?
 

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