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What is the de Broglie wavelength of this electron?

  • Thread starter gnozahs
  • Start date
1. Homework Statement
What is the de Broglie wavelength of this electron?
Given is 500 eV


2. Homework Equations
KE= 1/2 mv^2
1 eV=1.602x19^-19 J


3. The Attempt at a Solution
I converted the 500 eV to 8.01x10^-17 via the given conversion. Now I'm stuck.
 
The deBroglie wavelength is given by the relation

[tex]\lambda = \frac{h}{p}[/tex]

where [itex]h[/itex] is the plank constant and [itex]p[/itex] is momentum. I'm assuming the number in eV you were given is the kinetic energy of the electron--you can look up its mass to get it in terms of momentum through

[tex] T \text{(kinetic energy)}=\frac{p^2}{2m}[/tex]

Can you figure how to get the wavelength of it from this?
 

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