What is the definition of log(P) in the von neumann entropy formula?

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The von Neumann entropy is defined as S(P) = -tr(P*log(P)), where P is a density matrix. The discussion clarifies that log(P) can be defined using the eigenvalues of P, leading to the conclusion that S(P) equals the Shannon entropy H({k}) of those eigenvalues. The trace operation is noted to be independent of the representation of the density matrix. Additionally, an alternative expression for entropy is provided as S = -k⟨ln(ρ)⟩, which resembles Gibbs' entropy. This discussion highlights the relationship between quantum mechanics and information theory through the lens of entropy definitions.
trosten
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Let P be a density matrix. Then the von neumann entropy is defined as
S(P) = -tr(P*log(P))

But how is log(P) defined ?

--edit--
found the answer. the trace is independent of representation so that if P is diagonalized with eigenvalues {k} then S(P) = H({k}) where H is the shannon entropy.
 
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ln(P) = -\sum_{n=1}^\infty \frac{1}{n}(I-A)^n
 
trosten said:
found the answer. the trace is independent of representation so that if P is diagonalized with eigenvalues {k} then S(P) = H({k}) where H is the shannon entropy.
right. Usually easier by the way !
 
The definition is really

S:=-k\langle \ln\hat{\rho}\rangle_{\hat{\rho}}

,quite similar to Gibbs' entropy.

Daniel.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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