What is the definition of the transverse mode in QFT?

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SUMMARY

The transverse mode in Quantum Field Theory (QFT) is defined by the condition that the divergence of the transverse component of a vector field, denoted as \(A^T_\mu(x)\), satisfies \(\partial^\mu A^T_\mu(x) = 0\). This definition is crucial for understanding the behavior of massive spin-1 particles. The notation used in the discussion indicates that \(A^T_\mu(x)\) represents the transverse part of the vector field \(A_\mu(x)\), which can be expressed as \(A_\mu(x) = A^T_\mu(x) + \partial_\mu \pi(x)\), where \(\pi(x)\) is a scalar field.

PREREQUISITES
  • Understanding of Quantum Field Theory (QFT) principles
  • Familiarity with vector fields and their components
  • Knowledge of covariant and contravariant indices
  • Basic grasp of the mathematical notation used in QFT
NEXT STEPS
  • Study the derivation of the transverse condition in QFT
  • Learn about the role of scalar fields in vector field decomposition
  • Explore the implications of gauge invariance in massive spin-1 particles
  • Review Schwartz's QFT textbook for foundational concepts and notation
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This discussion is beneficial for students and researchers in Quantum Field Theory, particularly those focusing on the properties of vector fields and their transverse components in the context of massive spin-1 particles.

Silviu
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Hello! I am reading some QFT and at a point I read that any vector field (here we are working with massive spin 1 particles) can be written as: $$A_\mu(x)=A^T_\mu(x)+\partial_\mu\pi(x)$$ with $$\partial_\mu A^T_\mu(x)=0$$ They don't talk about notation, but from the context I understand that ##A^T_\mu(x)## is the transverse component of ##A_\mu(x)##. Is ##\partial_\mu A^T_\mu(x)=0## the definition of the transverse component? And if so, why? Thank you!
 
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Silviu said:
Hello! I am reading some QFT and at a point I read that any vector field (here we are working with massive spin 1 particles) can be written as: $$A_\mu(x)=A^T_\mu(x)+\partial_\mu\pi(x)$$ with $$\partial_\mu A^T_\mu(x)=0$$ They don't talk about notation, but from the context I understand that ##A^T_\mu(x)## is the transverse component of ##A_\mu(x)##. Is ##\partial_\mu A^T_\mu(x)=0## the definition of the transverse component? And if so, why? Thank you!
Yes, that's the definition. Note that you meant ##\partial^\mu A^T_\mu(x)=0##.
 
nrqed said:
Note that you meant ##\partial^\mu A^T_\mu(x)=0##.
He might not be if he is reading Schwartz's QFT book. If I remember correctly, Schwartz starts by saying that he takes it for granted that students know that when summation inices appear one is covariant and the other contravariant and therefore puts all indices as subindices.
 
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