What is the degree of dissociation of N2O4 at 100°C and 1 atm?

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Discussion Overview

The discussion revolves around calculating the degree of dissociation of N2O4 at 100°C and 1 atm, specifically focusing on the vapour density and its relation to the dissociation reaction N2O4(g) ⇌ 2NO2(g). Participants are attempting to derive the degree of dissociation and the equilibrium constant Kp using the provided vapour density value.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • The degree of dissociation is proposed to be calculated using the formula α = (Dt - Do) / Do, where Dt is the theoretical vapour density and Do is the observed vapour density.
  • Participants question the clarity of the original post, specifically asking for definitions of Dt and Do, and the significance of the value 92, which is identified as the molar mass of N2O4.
  • There is a suggestion that the original poster may have omitted necessary details in their explanation, leading to confusion about the problem's solvability.
  • One participant confirms the understanding of Dt and Do as the theoretical and observed vapour densities at equilibrium, but expresses concern that their calculations are yielding incorrect results.

Areas of Agreement / Disagreement

Participants generally agree on the definitions of Dt and Do, as well as the significance of the molar mass of N2O4. However, there is disagreement regarding the completeness of the problem statement and the correctness of the calculations, indicating that the discussion remains unresolved.

Contextual Notes

There is uncertainty regarding the completeness of the information provided in the original post, which may affect the ability to solve the problem accurately. The relationship between the vapour densities and the degree of dissociation is not fully elaborated, leading to potential gaps in understanding.

utkarshakash
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Homework Statement


Vapour density of [itex]N_2O_4[/itex] which dissociated according to the equation
[itex]N_2O_4(g) \Leftrightarrow 2NO_2(g)[/itex] is 25.67 at 100°C and a pressure of 1 atm. Calculate the degree of dissociation and [itex]K_p[/itex] for the reaction

Homework Equations



The Attempt at a Solution


[itex]\alpha = \frac{D_t-D_o}{D_o}[/itex]

[itex]D_t = \frac{92}{2}[/itex]
Plugging in the values does not yield desired answer.
 
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Please elaborate on what you are doing. What are Dt and D0? What is 92?

Is that the whole question? Either I am missing something or it can't be solved as given.
 
Borek said:
Please elaborate on what you are doing. What are Dt and D0? What is 92?

Is that the whole question? Either I am missing something or it can't be solved as given.

I suppose the OP directly posted the equations without showing how he/she has got it. If i remember correctly, Dt and Do are the theoretical and observed vapour density of a mixture at equilibrium. 92 is the molar mass of N2O4.
 
Pranav-Arora said:
I suppose the OP directly posted the equations without showing how he/she has got it. If i remember correctly, Dt and Do are the theoretical and observed vapour density of a mixture at equilibrium. 92 is the molar mass of N2O4.

Yes that's right. But the answer which I'm getting is wrong.
 

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