What is the dependence on w of intensity in single slit diffraction?

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neelakash
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Homework Statement



Interesting Problem...

monochromatic light of wavelength [tex]\lambda[/tex] falls on a slit and is transmitted as

t=1 for 0<x<(d/2)
t=-1 for (-d/2)<x<0
t=0 otherwise...

Define [tex]\ w[/tex]=[tex]\ k(d/2)[/tex][tex]\sin[/tex][tex]\theta[/tex]...[most possibly,if I can exactly remember...]

Now what should be the dependence on w of Intensity [tex]\I(\theta)[/tex]?

It was a multiple choice question and a number of options were given...

(A) [tex]\frac{sin^2 \omega}{\omega^2}[/tex]

(B) [tex]\frac{sin^2 \frac{\omega}{2}}{\omega^2}[/tex]

(C) [tex]\frac{cos^2 \omega}{\omega^2}[/tex]

(D) [tex]\frac{sin\omega}{\omega}[/tex]


Homework Equations



The Attempt at a Solution



(B) seems plausible to me as it considers w/2...Note that in this particular problem,the phasor amplitudes are different about the centre.If you take the geometrical point of view,the phasor vectors will be a bit different than they are shown normally.
[I do not know which classical book uses the geometrical phasor derivation...I saw it in Resnick Halliday Krane's fifth volume.]
 
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t is transmission co-efficient
 
neelakash said:
(B) seems plausible to me as it considers w/2...
Answer (B) is correct.
 
Ok

Any better argument?
 
Exactly,I was talking of this derivation.