What is the depth of the weight below the beam?

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Homework Help Overview

The problem involves a weight supported by two strings of different lengths attached to a horizontal beam, with the goal of determining the "depth" of the weight below the beam. The original poster seeks clarification on the meaning of "depth" in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the interpretation of the weight's representation, with some suggesting it should be treated as a point mass. Questions arise regarding the accuracy of the original diagram and the equilibrium conditions relevant to the problem.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's diagram and suggesting revisions. Some guidance has been offered regarding the interpretation of the problem, but no consensus has been reached on the exact approach to take.

Contextual Notes

There is mention of the context in which the homework was assigned, with participants questioning the course and the specific requirements of the problem. Additionally, there are indications of confusion regarding the direction of forces represented in the diagram.

Shivansh Mathur
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Homework Statement


A weight is supported by 2 stings 1.3m and 2m long fastened to two points on a horizontal beam 2m apart. What is the depth of the weight below the beam?

My question is- what does it mean by the "depth" of the beam?

Homework Equations


i'm new to the topic.

The Attempt at a Solution


the diagram which i made:
IMG_0102.JPG

please help in finding a solution. Thanks
 
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As I understand the problem, the weight is not a beam as you have drawn it but is, instead, small enough to be considered to be a point. The strings hang at angles to support it.
 
I don't think your picture is right. Re-read the problem and try again.

Also, you should write down the equilibrium conditions as the relevant equations.
 
In which context did you get this homework or which cours are you attending? Because to me it seems, that you only have to calculate the distance of the weight from the beam - maybe for the center of the mass (which you have already found, but the force (vector) - if the drawn arrow should indicate this - points in the wrong direction).
 
The new diagram should be like this then:
IMG_0103.JPG
 
stockzahn said:
In which context did you get this homework or which cours are you attending? Because to me it seems, that you only have to calculate the distance of the weight from the beam - maybe for the center of the mass (which you have already found, but the force (vector) - if the drawn arrow should indicate this - points in the wrong direction).

no no! that arrow i have just drawn to label, it's not the direction of the vector.
 
Shivansh Mathur said:
The new diagram should be like this then:
Yes, that's it.
 

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