What is the depth x of the oil?

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SUMMARY

The discussion focuses on calculating the depth of oil (x) in a borehole that is 2000 meters deep, containing both oil and water. The pressure at the bottom of the borehole is 17.5 MPa, with oil density at 830 kg/m³ and water density at 1000 kg/m³. The initial calculation incorrectly considers only the water's contribution to pressure. The correct approach involves accounting for both oil and water, leading to the equation: 17.5 × 10^6 = 830 × g × x + 1000 × g × (2000 - x).

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Homework Statement


The bore hole of depth 2000m contains both oil and water as shown. The pressure at the bottom is 17.5MPa. The density of the oil is 830kgm^-3 and the density of the water is 1000kgm^-3.
http://img384.imageshack.us/img384/6944/10062008fj0.png
What is the depth x of the oil?

Homework Equations


Pressure = Height x Density x Gravity

The Attempt at a Solution



17.5 \times 10^6 = x \times 1000 \times 9.81

x = \frac{17.5 \times 10^6}{1000 \times 9.81}

x = 1789.893986m

Where did I go wrong?
 
Last edited by a moderator:
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Both oil and water have a contribution in the pressure:

p = \rho g \Delta h

So we get:

17.5 \cdot 10^6 = 830 \cdot g \cdot x + 1000 \cdot g \cdot(2000-x)
 

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