What is the Derivative of (1+tanx)?

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SUMMARY

The first derivative of the function (1 + tan(x)) is calculated using the quotient rule, resulting in sec^2(x). The derivative of the constant 1 is 0, while the derivative of tan(x) is sec^2(x). This identity simplifies the differentiation process, making it easier for students to handle similar problems in calculus.

PREREQUISITES
  • Understanding of basic calculus concepts, specifically derivatives.
  • Familiarity with the quotient rule for differentiation.
  • Knowledge of trigonometric functions, particularly tangent and secant.
  • Ability to manipulate mathematical identities and expressions.
NEXT STEPS
  • Study the quotient rule in detail to apply it to more complex functions.
  • Learn about the derivatives of other trigonometric functions, such as cotangent and cosecant.
  • Explore the application of derivatives in real-world problems, particularly in physics and engineering.
  • Practice solving derivative problems involving composite functions and implicit differentiation.
USEFUL FOR

Students studying calculus, mathematics educators, and anyone looking to strengthen their understanding of differentiation techniques and trigonometric identities.

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real quick review needed, I'm working through the quotient rule on a problem and need the first derivative of:

(1+tanx)

is it simply equal to:

(0 + sec^2x * 1)
(sec^2 x)

??
 
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yes that's correct

1 = 0, \tan{x}=\sec^2{x}
 
rocophysics said:
1 = 0
Geez, that's a nice identity.
I wish I could use that on my exam, it would make life a lot easier :biggrin:
 
CompuChip said:
Geez, that's a nice identity.
I wish I could use that on my exam, it would make life a lot easier :biggrin:
lol, you know what i meant ;)
 
Yeah, I know you meant

1' = 0, \tan(x)' = \sec^2(x)
where ' = \frac{\rm d}{{\rm d}x}.
 

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