Undergrad What is the derivative of a matrix transpose?

Click For Summary
SUMMARY

The derivative of a matrix transpose is not directly computed; instead, one takes the derivative of the functions that constitute the vector. In the context of the discussion, ##\dot{q}## represents the time derivative of the vector ##\vec{q}##, which is defined as ##\frac{d\vec{q}}{dt}##. The conversation emphasizes the importance of understanding that derivatives apply to the components of vectors rather than the matrices themselves. Additionally, the discussion clarifies that when taking partial derivatives, one should focus on the function H with respect to variables p and q.

PREREQUISITES
  • Understanding of vector calculus
  • Familiarity with matrix operations
  • Knowledge of time derivatives in physics
  • Basic concepts of partial derivatives
NEXT STEPS
  • Study the properties of matrix derivatives in linear algebra
  • Learn about vector calculus and its applications in physics
  • Explore the concept of Jacobian matrices and their derivatives
  • Investigate the relationship between matrix transposes and their derivatives
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are working with vector calculus and matrix operations, particularly those interested in understanding derivatives in the context of dynamic systems.

dynamicskillingme
Messages
26
Reaction score
0
Hi! As the title says, what is the derivative of a matrix transpose?

e0105b10b69da68fd563eb3008f2319c.png

I am attempting to take the derivative of \dot{q} and \dot{p} with respect to p and q (on each one).

Any advice?
 
Physics news on Phys.org
Also
1c3f5e999304f25920fca3a3694e2ea0.png
 
dynamicskillingme said:
Hi! As the title says, what is the derivative of a matrix transpose?

e0105b10b69da68fd563eb3008f2319c.png

I am attempting to take the derivative of \dot{q} and \dot{p} with respect to p and q (on each one).

Any advice?
Your question doesn't make sense to me. You don't take the derivative of a matrix (or a matrix transpose) -- you take the derivative of the functions that make up a vector (or its transpose).

You have ##\vec{q} = \begin{bmatrix} q_1 \\ q_2 \\ \vdots\\ q_n \end{bmatrix}##. ##\dot{q}## usually means the derivative with respect to t of ##\vec{q}##: ##\frac{d\vec{q}}{dt}##.

Without knowing more about this problem, I would guess that ##\dot{q}## is a vector that contains the derivatives (with respect to time) of ##q_1, q_2, \dots, q_n##.

In your second post, they are taking partials of H with respect to p and q, not the partials of p or q with respect to each other.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 15 ·
Replies
15
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
593