Using a determinant to find the area of the triangle (deriving the formula)

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SUMMARY

The discussion focuses on deriving the formula for the area of a triangle using determinants. Specifically, it highlights the determinant of a 3x3 matrix, where one vertex is placed at the origin, and the matrix is structured as follows: $$\det \begin{pmatrix}a & b & 1 \\ c & d & 0 \\ e & f & 0\end{pmatrix}$$. The equivalence of this determinant to $$\det \begin{pmatrix} c & d \\ e & f\end{pmatrix}$$ is established through cofactor expansion along the third column. This method clarifies the inclusion of the extra row and column in the determinant calculation.

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Sunwoo Bae
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Homework Statement
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Relevant Equations
Det(A) = det(A^T) determinant of transpose equals determinant of the original matrix
7AD7CFA7-C0E0-47CF-9FDA-EE6343366B2C.jpeg

This is the question. The following is the solutions I found:

D91C0495-3838-4DFA-9EAE-B1A8928292BA.jpeg

I understand that the first line was derived by setting one vertex on origin and taking the transpose of the matrix. However, I cannot understand where the extra row and column came from in the second line. Can anyone explain how the formula is derived?

Thank you!
 
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This is due to the fact that
$$\det \begin{pmatrix}a & b & 1 \\ c & d & 0 \\ e & f & 0\end{pmatrix}= \det \begin{pmatrix} c & d \\ e & f\end{pmatrix}$$

To see this, develop the ##3\times 3##-determinant along the third column (cofactor expansion), or if you don't know about this calculate both sides and see that they are equal.
 
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