What is the Diameter of an Oil Slick Spreading on a Lake?

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Homework Help Overview

The discussion revolves around estimating the diameter of an oil slick formed by one liter of oil spilled on a lake, assuming the oil spreads uniformly to a thickness of one molecule. The problem involves concepts from fluid dynamics and molecular volume calculations.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss converting the volume of oil into cubic meters and calculating the volume of an individual oil molecule. There are attempts to clarify the correct formula for volume and the units involved. Some participants explore how to derive the surface area from the volume and thickness of the oil slick.

Discussion Status

The discussion includes various attempts to calculate the volume of an oil molecule and the number of molecules in one liter of oil. Participants are actively engaging with the problem, questioning assumptions, and providing guidance on how to approach the calculations without reaching a final solution.

Contextual Notes

There is some confusion regarding the units of volume and the correct formula for calculating the volume of a molecule. Participants are also exploring the implications of assuming the oil slick forms a circular shape on the lake.

homeworkboy
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One liter ( 1000 cm^3) of oil is spilled onto a smooth lake.If the oil spreads out uniformly until

it makes an oil slick just one molecule thick, with adjacent molecules just touching, estimate

the diameter of the oil slick. Assume the oil molecules have a diameter of 2X10^-10m.
 
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homeworkboy said:
One liter ( 1000 cm^3) of oil is spilled onto a smooth lake.If the oil spreads out uniformly until

it makes an oil slick just one molecule thick, with adjacent molecules just touching, estimate

the diameter of the oil slick. Assume the oil molecules have a diameter of 2X10^-10m.

Welcome to PF.

How would you approach the problem?
 
Well i would first convert the volume of water into m3 which is 1. so...then i can't think of anythin..i need help solving this
 
homeworkboy said:
Well i would first convert the volume of water into m3 which is 1. so...then i can't think of anythin..i need help solving this

What volume of water? I will presume you mean the volume of oil. That may not be necessary.

What is the volume of an oil molecule of the given diameter? Maybe start there?
 
sorry i meant volume of oil...well volume of oil molecule will be Pi r^2 so..22/7 * (1 * 10^-10)^2
so 3.14 X 10^-20
 
homeworkboy said:
sorry i meant volume of oil...well volume of oil molecule will be Pi r^2 so..22/7 * (1 * 10^-10)^2
so 3.14 X 10^-20

What is volume in units of again?
 
its m3
 
homeworkboy said:
its m3

What are the units of the answer you supplied for volume?
 
the unit is meter cube or litres
 
  • #10
homeworkboy said:
the unit is meter cube or litres

No actually it's not. You supplied an answer that was in m2 not m3.

The formula for volume of a sphere is not pi R2.
 
  • #11
sorry volume is ( π X d³)/6
 
Last edited:
  • #12
homeworkboy said:
sorry volume is ( π X d³)/6

OK so now what is the volume of the molecule?

Then next how many of those are there in the volume of oil?
 
  • #13
then the vol of molecule is 4.2 X 10^-30...so no. of those in 1 L are 2.4 X 10^29...what next
 
  • #14
homeworkboy said:
then the vol of molecule is 4.2 X 10^-30...so no. of those in 1 L are 2.4 X 10^29...what next

You previously calculated the area that one of these would cover ... so knowing how many you have now what is the area they will spread out to according to the statement of the problem?
 
  • #15
first, convert the volume of oil from cm^3 to m^3. now we work backwards
first divide the volume of oil by the thickness of one molucule by doing this what happens is m3/(m becomes m^2 which is area, therefore you have now solved for the surface area. now since it says diameter I am assuming the lake is circular, so just plug into the equation for area of a circle and work backwards
a = ╥r2
a/╥ = r2
sqrt(a/╥) = r
now just double too find the diameter and you have your answer. its simple geometry, you probably just thought a little too hard about it.
 
  • #16
thanks a lot man..i really understood the way u explained...i have one more doubt that i posted earlier but no one replied here's the question...

For small angles theta, the numerical value of sin theta is approximately the same as the

numerical value of tan theta.Find the largest angle for which sine and tangent agree to within

two significant figures.Thank you for all the help
 
  • #17
hmm well basically its saying find the highest value of Ø such as sin(Ø) = tan(Ø) up to the second decimal place. I am guessing a lot of guessing/checking?
 

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