What is the displacement of an ion in a mass spectrometer?

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SUMMARY

The displacement of an ion in a mass spectrometer following a semicircular path with a radius of 15.2 cm can be calculated using the Pythagorean theorem. The distance traveled by the ion is determined by the formula s = πr, resulting in a distance of approximately 47.8 cm. The displacement, which is the straight-line distance from the starting point to the endpoint, is calculated as the diameter of the semicircle, yielding a displacement of 30.4 cm.

PREREQUISITES
  • Understanding of semicircular motion in mass spectrometry
  • Familiarity with the Pythagorean theorem
  • Basic knowledge of circular geometry
  • Ability to perform calculations involving π (pi)
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Homework Statement


An ion in a mass-spec follows a semicircular path of radius 15.2 cm.
a)What are the distance it travels
b)The magnitude of its displacement

The Attempt at a Solution



a) s = pi.r
r = 15.2cm

s = pi(15.2cm)

b) what is part(b) asking?
 
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Ok I think I had it figured out.

particle at position(15.2,15.2)
Pythagoras theorem should solve it.
 

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