What is the distance traveled by the block in the next 5.70 s?

[Heat]

Homework Statement

A dockworker applies a constant horizontal force of 74.0 N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves a distance 13.0 m in a time 4.50 s.

If the worker stops pushing at the end of 4.50 s, how far does the block move in the next 5.70 s?

Homework Equations

F=MA

The Attempt at a Solution

I solved for mass, using the equation,

m = 57.6


now that I know mass

how do I get started?

I tried doing (74/57.6)5.70

 

[learningphysics]

You don't need the mass in this question or the force. You just need the velocity at the end of the 4.50s.

Then you answer would be v*5.70s

 

[Heat]

velocity should be then 13/4.50? am i right..

 

[learningphysics]

velocity should be then 13/4.50? am i right..

No. That is only for constant velocity... the block is accelerating.

 

[Heat]

would velocity then be 5.78m/s?

 

[learningphysics]

would velocity then be 5.78m/s?

Yup.