What is the domain, range, and asymptotes for these exponential functions?

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Homework Help Overview

The discussion revolves around identifying the domain, range, and asymptotes of two rational functions presented by the original poster. The functions in question are y = 1/(x+3) and y = (-2/(x-3)) + 2, which some participants note are not exponential functions.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the correct interpretation of the functions, with some clarifying the notation used. There is an exploration of how to graph the first function by relating it to the basic function of 1/x and considering translations.

Discussion Status

The discussion is ongoing, with some participants providing clarifications and corrections regarding the notation. There is a suggestion that the original poster should provide their own work to facilitate further assistance.

Contextual Notes

Participants emphasize the importance of correctly writing mathematical expressions and the need for the original poster to demonstrate their understanding of the concepts of domain, range, and asymptotes.

striker_77
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hey i have some hmwk and need help with a few questions. I would appreciate it if i could get some explanations :)

1i) state the domain, range and the equations of the asymptotes.

a) y= 1 / x+3

b) y= (-2 / x-3) + 2
 
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striker_77 said:
hey i have some hmwk and need help with a few questions. I would appreciate it if i could get some explanations :)

1i) state the domain, range and the equations of the asymptotes.

a) y= 1 / x+3

b) y= (-2 / x-3) + 2

You are not writing those properly. That is aside from their not being exponential functions. What you wrote can be exactly represented as:
[tex]\[<br /> \begin{array}{l}<br /> y = \frac{1}{x} + 3 \\ <br /> \\ <br /> {\rm AND} \\ <br /> \\ <br /> y = \,\; - \frac{2}{{x - 3}} + 2 \\ <br /> \end{array}<br /> \][/tex]
 
yea sorry i didnt know how to write it like that, the second one is right, but for the first one the "+3" is with the denominator.
 
i think i got the first one :S. is it that i draw the basic function of 1/x, then move that 3 units to the left?
 
striker_77 said:
i think i got the first one :S. is it that i draw the basic function of 1/x, then move that 3 units to the left?

That is correct.
 
Which is [tex]y=\frac{1}{x}[/tex] under a translation of [tex]\begin{bmatrix} 3 \\ 0 \end{bmatrix}[/tex]
 
First, as the very first thread says, this is NOT the place to post homework! I am moving this to the precalculus- homework forum.

Second, you MUST post some of your own work so we will know what kind of help you need. Writing out the definition of "domain", "range", and "asymptote" might be a good place to start.

Third, if you can't use LaTex, you can certainly use parentheses!

Most people would interpret 1/x+ 3 as (1/x)+ 3. You mean 1/(x+3).

Similarly, most people would interpret (-2 / x-3) + 2 as ((-2/x)- 3)+ 2.
You mean -2/(x-3)+ 2.
 
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