What is the Effect of Angular Acceleration on a Block on a Conical Surface?

danago
Gold Member
Messages
1,118
Reaction score
4
http://img357.imageshack.us/img357/6476/80028206ag6.gif

This question had me a little confused. I started by drawing a free body diagram of the block:

http://img246.imageshack.us/img246/9121/59804825wo9.gif

Where W is the weight, N is the normal force and F is the friction force.

Because the cone is spinning, does that mean there will also be a frictional force in the direction extending out/into the page?

Since the block will effectively be moving in a circular path, its net acceleration will be given by:

[tex] <br /> \overrightarrow {\bf{a}} = r\alpha \underline {\widehat{\bf{t}}} + \omega ^2 r\widehat{\underline {\bf{n}} }<br /> [/tex]

The question states that the angular acceleration increases very slowly? Can i approximate this to be zero?

Thanks in advance for any help.
Dan.
 
Last edited by a moderator:
on Phys.org
Yes, the frictional force will apply along the surface on the cone. The question asks you the maximum angular velocity with which the cone can be spinning so that the block does not slip. The angular velocity is said to very slowly increase just so that we may assume it is continuous, and can take every angular velocity before the critical velocity at which the block slips. You can not approximate it with zero because then the angular velocity doesn't increase at all, which is critical to the question. Sadly, I know enough to tell you what's wrong, but not enough to tell you how to proceed =[ .
 
danago said:
The question states that the angular acceleration increases very slowly? Can i approximate this to be zero?

You'll have to, because they don't tell you what it is.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
Replies
15
Views
2K
  • · Replies 10 ·
Replies
10
Views
9K
  • · Replies 8 ·
Replies
8
Views
4K
Replies
6
Views
2K
  • · Replies 20 ·
Replies
20
Views
6K
Replies
9
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 3 ·
Replies
3
Views
3K