What is the effect of combining two sinusoidals with different frequencies?

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SUMMARY

The discussion focuses on the combination of two sinusoidal functions, specifically sin(3t) and -cos(πt). The key takeaway is that when these two functions are combined, the resulting motion oscillates at the slower frequency of -cos(πt), while being modulated by the faster frequency of sin(3t). The equation Cos(A) - Cos(B) = -2sin([A+B]/2)sin([A-B]/2) is crucial for understanding the transformation of these functions. Graphing the combined signal over different time intervals is recommended for better visualization of the modulation effect.

PREREQUISITES
  • Understanding of sinusoidal functions and their properties
  • Familiarity with trigonometric identities, particularly Cos(A) - Cos(B)
  • Knowledge of angular frequency and its relationship to period (T)
  • Ability to graph functions and interpret oscillatory behavior
NEXT STEPS
  • Learn about Fourier series and how they represent periodic functions
  • Explore the concept of amplitude modulation in signal processing
  • Study the effects of phase shifts on sinusoidal functions
  • Investigate the graphical representation of combined sinusoidal functions
USEFUL FOR

Students studying physics or mathematics, particularly those focusing on wave motion, signal processing, or trigonometric functions. This discussion is beneficial for anyone looking to understand the interaction of sinusoidal waves with different frequencies.

Physics2013
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Homework Statement


Find the frequency of the combined motion of sin(3t) - cos(Pi t)


Homework Equations


Cos(A) - Cos(B) = -2sin([A+B]/2)sin([A-B]/2)
f=1/T
Omega=2Pi/T

The Attempt at a Solution


sin(3t) - cos(Pi t) =
cos(3t - (Pi/2)) - cos(Pi t) =
-2sin({t[3 + pi]/2} - (pi/4))sin({t[3 - pi]/2} - (pi/4))

Now, I tried taking the average of omega(1) and omega(2), but this is not correct.
I am confused on what the next step is.
 
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Physics2013 said:

Homework Statement


Find the frequency of the combined motion of sin(3t) - cos(Pi t)


Homework Equations


Cos(A) - Cos(B) = -2sin([A+B]/2)sin([A-B]/2)
f=1/T
Omega=2Pi/T

The Attempt at a Solution


sin(3t) - cos(Pi t) =
cos(3t - (Pi/2)) - cos(Pi t) =
-2sin({t[3 + pi]/2} - (pi/4))sin({t[3 - pi]/2} - (pi/4))

Now, I tried taking the average of omega(1) and omega(2), but this is not correct.
I am confused on what the next step is.

When you have two sinusoidals multipled together, and the frequency of one is much larger/faster than the frequency of the other, the overall signal appears to oscillate at the smaller/slower frequency, and is modulated by the much faster sinusoid (you end up with a "bumpy" sinusoid where the bumps have a very fast frequency, but their amplitude is much smaller and they are often almost unnoticable). Try graphing your signal over a very short (much less than the period of the slower sinusoid) and a longer (at least ione full period of the slower sinusoid) time interval to better visualize what's going on.
 

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