What is the Electric Field Between Deflection Plates in a TV Tube?

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SUMMARY

The electric field between deflection plates in a TV tube can be calculated using the force experienced by the electron beam. Given a force of 3.0 x 10-6N, the electric field (E) can be determined using the formula E = F/q, where F is the force and q is the charge of the electron. Additionally, when a globe acquires a charge of -8.0 x 10-9C, the electric field at a distance of 0.40m can be calculated using the formula E = k * |Q| / r2, where k is Coulomb's constant, Q is the charge, and r is the distance from the charge. Gauss's law simplifies the calculation by allowing the assumption of uniform charge distribution over the sphere.

PREREQUISITES
  • Understanding of electric fields and forces
  • Familiarity with Coulomb's law
  • Knowledge of Gauss's law
  • Basic concepts of charge and its effects
NEXT STEPS
  • Study the application of Coulomb's law in electric field calculations
  • Learn about Gauss's law and its implications for spherical charge distributions
  • Explore the concept of electric field strength and its relation to force and charge
  • Investigate the behavior of charged particles in electric fields
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Students in physics, electrical engineers, and anyone interested in understanding electric fields and their applications in devices like TV tubes.

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Homework Statement


An electron beam in the TV tube is steered across the screen by the field between two charged plates. If the electron experiences a force of 3.ox10(to the negative 6th)N, how large is the field between the deflection plates?



2. Homework Statement
The custodian dusts off a globe with a duster, causing the globe to acquire a charge of -8.0x10(to the negative 9th)C. What is the magnitude and direction of the electric field at a point 0.40m from the center of the charged globe?
 
Physics news on Phys.org
For number one: What is the force on a point particle with charge q in a uniform field E?

For number two: Assuming the charge distributes uniformly over the sphere, what simplification can you make? Think Gauss's law.
 

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