What is the electric field problem involving two point charges?

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Homework Help Overview

The discussion revolves around an electric field problem involving two point charges, specifically determining the position along the positive x-axis where the electric field is zero due to these charges. The charges are given as q1 = 4.0×10-6 C and q2 = -1.0×10-6 C, located at specified positions on the x-axis.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conditions under which a test charge experiences no net force due to the two point charges. There is an exploration of the forces acting on the test charge and the requirement for these forces to be equal in magnitude but opposite in direction. Questions arise regarding the derivation of the distance expressions used in the force equations.

Discussion Status

The conversation is active, with participants sharing their reasoning and attempting to clarify the relationships between the distances and forces involved. Some guidance has been provided regarding the setup of the problem, though there is no explicit consensus on the final answer or method.

Contextual Notes

Participants are working under the constraints of the problem as stated, with specific positions for the charges and the requirement that the test charge must be placed on the positive x-axis. There is an emphasis on understanding the forces involved rather than simply arriving at a solution.

Ryo124
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Electric Field Problem -Easy please help

Homework Statement



Two point charges, q1 = 4.0×10-6 C and q2 = -1.0×10-6 C, are located on the x-axis at x1 = -1.0 cm and x2 = 3.0 cm.

Determine the x coordinate of a point on the positive x-axis where the electric field is zero; i.e., a test charge placed at this point would experience no force.

Homework Equations



kq/(r^2)

The Attempt at a Solution



Don't know, please help, I would like to know how to solve this.
 
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I am not good in electric field. So, i will ... the problem with electrical force.
Let this test charge is +x cm from the origin.
Experience no force: The forces that act on this test charge by charge 1 and 2 must be the same in magnitude but in opposite directions. one will repel the test charge in one direction, the other will attract in the opposite direction.
Considering only he magnitude of the two forces:
k*q3*q1/(x-3)^2 = k*q3*q2/(x+1)^2 [remember to take the magnitude only especially the charge]
solving for x, you suppose to get 7 cm and 5/3 cm .
The answer will be 7 cm. since this test charge cannot be less than +3 cm from the origin, otherwise zero net force will not be possible since the the two forces acting on test charge are in the same direction.
 
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Yes, 7cm is the right answer, thank you Leong. I understand that the forces are equal yet opposite, but where did you get the equation
k*q3*q1/(x-3)^2 = k*q3*q2/(x+1)^2 from? What I really mean is where does (x-3) and (x+1) come from?
 
x-3 is the distance between q3 and q2. x + 1 is the distance between q3 and q1. draw the diagram, put the test charge to the left of q2, thenit will be clearer.
 
Last edited:

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