What is the energy lost due to friction?

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SUMMARY

The discussion centers on calculating the energy lost due to friction for a sledge loaded with bricks, weighing 18.0 kg, being pulled at a constant speed with a rope inclined at 20° above the horizontal. The coefficient of kinetic friction is 0.500. The correct tension in the rope is determined to be 79.4 N, factoring in both the x-component and the y-component of the tension, which affects the normal force. The participant initially miscalculated the tension due to neglecting the y-component, leading to confusion in subsequent calculations.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of trigonometric functions, specifically sine and cosine
  • Familiarity with the concept of kinetic friction and its coefficient
  • Basic principles of work and energy in physics
NEXT STEPS
  • Calculate the normal force acting on the sledge using the y-component of tension
  • Determine the work done by the rope using the formula W = F × d × cos(θ)
  • Explore the relationship between tension, friction, and normal force in inclined scenarios
  • Study examples of energy loss due to friction in different physical systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and forces, as well as educators looking for practical examples of friction and tension in real-world applications.

tristan_fc
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Okay, I have this problem I've been fighting with for a couple of hours now. I have the answers for it, but I can't figure out how they're the answers. Here's the problem:

A sledge loaded with bricks has a total mass of 18.0 kg and is pulled at constant speed by a rope. The rope is inclined at 20° above the horizontal, and the sledge moves a distance of 20.0 m on a horizontal surface. The coefficient of kinetic friction between the sledge and surface is 0.500.

A) What is the tension of the rope?

B) How much work is done on the sledge by the rope?

c) What is the energy lost due to friction?

If I got the first answer right, I could do the rest, but that's where I'm stuck. I know I need to find the x-component of the tension, and then use trig to find the tension of the rope. What I did was this:

Tx = 0.5*18*9.8 = 88.2

That's wrong. I know it's wrong, because the tension I found with that value was approx. 82.9. The answer is supposed to be 79.4. I know it's wrong, because I'm not considering the y-component of tension, but I don't know how to do that. Anybody have any ideas? This is a web-based assignment, due by midnight central time. (4 hours)Thanks for your help.
 
Last edited:
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It's wrong because you forgot that the normal force is reduced by the vertical component of the tension.

Is that enough to get you started again?
 
Well that's what I said.

I figured it out though. I remembered that you have to use tangent. Thanks though. :)
 

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