What is the energy of the electron just before it hits

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SUMMARY

The kinetic energy of a 300 eV electron just before it strikes an upper metal plate in a 400 V potential difference is 500 eV. The electron maintains its initial energy in the x-direction while gaining an additional 200 eV from the vertical component due to the potential difference. The confusion arises from the incorrect assumption that energy can be treated as a vector; instead, the total energy is simply the sum of the energies in both directions. Therefore, the correct calculation is 300 eV + 200 eV = 500 eV.

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Homework Statement


A 300 eV electron is aimed midway between two parallel metal plates with a potential difference of 400 V. The electron is deflected upwards and strikes the upper plate as shown.
What would be the kinetic energy of the electron just before striking the metal plate?

Homework Equations


Magnitude of the resultant vector =
= Sqrt [ Ex^2 + Ey^2 ] = Sqrt [ (300eV)^2 + (200eV)^2 ] = Sqrt [ (2e2)^2 + (3e2)^2 ] = 360 eV

The Attempt at a Solution


The electron energy in x direction is unaffected by the 400 V field. So it is present just before hitting the plate.
And the electron goes thru half of the 400V = 200 V vertically picking up energy of 200 eV.
So the resultant total energy is the vector sum of the x and y components of 200eV and 300eV.
BUT
The answer sheet say the final energy before striking the plate is 500eV
I do not see why is is not 360eV as calculated above.

Thanks for your help
 
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paulfr said:
So the resultant total energy is the vector sum of the x and y components of 200eV and 300eV.
Energy is not a vector! (Just add them up.)
 

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