What is the energy of this electron

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SUMMARY

An electron accelerated through a potential difference of 2.0 x 104 V in a television picture tube gains an energy of 20,000 electron volts (eV), as confirmed by the calculation of electric potential energy using the formula delta V = delta Ep/q. The conversion from joules to electron volts is straightforward, yielding the same value of 20,000 eV. The calculated speed of the electron upon striking the screen is 8.4 x 107 m/s, consistent with the kinetic energy equation Ek = 0.5mv2. The discussion concluded that the answer key provided was incorrect regarding the energy in eV.

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  • Understanding of electric potential and electron volts (eV)
  • Familiarity with kinetic energy equations (Ek = 0.5mv2)
  • Basic knowledge of particle physics and elementary charge
  • Ability to perform unit conversions between joules and electron volts
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  • Study the relationship between potential difference and energy in electron volts
  • Learn about relativistic kinetic energy and its implications for high-speed electrons
  • Explore the concept of elementary charge and its role in particle physics
  • Review common misconceptions regarding energy units in physics
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Students in physics, particularly those studying electromagnetism and particle physics, as well as educators seeking to clarify concepts related to electron energy and potential differences.

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Homework Statement


An electron in the beam of a typical television picture tube is accelerated through a potential difference of 2.0*10^4 V before it strikes the face of the tube. What is the energy of this electron, in electron volts, and what is its speed when it strikes the screen?


Homework Equations


delta V = delta Ep/q
Ek=0.5mv^2


The Attempt at a Solution


well, I used the first equation to find its electric potential energy, which is (2.0*10^4)*(1.6*10^-19), and that gives me 3.2*10^-15J

then since it's asking in eV, and 1eV = 1.6*10^-19J, i do (3.2*10^-15)/(1.6*10^-19), which gives me 2*10^4eV (exact number as we started).

I don't see anything wrong with the procedure but the answer is 2*10^-4eV. what did i do wrong?

as for speed: (im using my 2*10^4eV as the energy)
Ek=0.5mv^2, and energy in J is 3.2*10^-15J
so 3.2*10^-15 = 0.5 (9.11*10^-31)v^2
that gives me 8.4*10^7m/s, which is exactly the same as the answer.

therefore I'm assuming the answer key for the energy in eV is wrong, what do you think?
 
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The definition of an electron volt is the energy gained by an elementary charge (e.g. the charge on proton or electron) when moved through a potential difference of one volt. This is why it is such a convenient unit of energy for particle physics. You know by definition that if an electron goes through potential difference of 2.0*10^4 volts, it now has an energy of 2.0*10^4 electron volts.

Conclusion 1: It wasn't necessary to multiply the voltage by the charge in coulombs to get the energy in joules first. You're measuring charge in units of "elementary charges" instead now.

Conclusion 2: Your answer key must be wrong.
 
Electron volts is weird. By definition, its 20,000V. I think its a misprint in your answer key and converting this potential energy to kinetic strikes me as sound.
 
denverdoc said:
Electron volts is weird. By definition, its 20,000V.

Huh? This doesn't make any sense. Did you understand what I wrote?
 
Shouldn't you use relativistic kinetic energy?
 
cepheid said:
Huh? This doesn't make any sense. Did you understand what I wrote?

I didn't, it was a simultaneous post, i was saying the same thing--by the definition of eV, the answer was 20,000.
 
yea, i asked my teacher and the answer was printed wrong. thanks guys.
 

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