- #1

jisbon

- 476

- 30

- Homework Statement
- An electron 1m from the left rod (2 micro C/m) released with initial velocity ##1.04*10^8 m/s## towards the right rod (-2 micro C/m). The length between 2 rods in 4m.

Find maximum distance it can go to the right.

- Relevant Equations
- -

Since electron will stop eventually due to efield,

equation is : ##v^2 = u^2 +2as##

Where v = 0 , u = ##1.04*10^8 m/s##

##a = \frac{qe}{m} =\frac{(1.6*10^{-19})(e)}{9.11*10^{-31}}##

##e = \frac{Q}{4\pi\epsilon(1)}+\frac{Q}{4\pi\epsilon(4-1)}##

Are the equations correct? Or is my concepts wrong?

equation is : ##v^2 = u^2 +2as##

Where v = 0 , u = ##1.04*10^8 m/s##

##a = \frac{qe}{m} =\frac{(1.6*10^{-19})(e)}{9.11*10^{-31}}##

##e = \frac{Q}{4\pi\epsilon(1)}+\frac{Q}{4\pi\epsilon(4-1)}##

Are the equations correct? Or is my concepts wrong?