What is the Energy Transmitted by a Plane EM Wave Passing Through a Window?

[Wesley Strik]

Homework Statement

In free space, the electric field of a plane EM wave is given by: E(z,t)= 50î cos[wt-kz]
where w= 6 x 10^15
and k=2x10^7
(A) calculate the amplitude of the magnetic field H
How much energy does this wave transmit in 30s when it passes through a window of dimensions 2mx3m if the EM wave is incident:
(b) normally on the window
(c) obliquely at an angle of 30 degrees with respect to the window normal

Homework Equations

Maxwell:
curl E= dB/dt
--------------- relation H and B---
H=B/mu0
mu0=4pi x 10 ^-7
----------------------------------------

The Attempt at a Solution

For (A) I relate the two fields via the Maxwell curl E= dB/dt which yields:
50k j cos(wt-kz) = w B
such that B= 50k/w cos (wt-kz)
the amplitude becomes 50k/w=(10^9)/(6x10^15)= 1/6 x 10^-6
now relate this to H=B/mu0 ---> (1/6 x 10^-6)/(4pi x 10^-7)= (10/6) / (4pi) =0.13 A/m

did I d (A) correclty, does the outcome make sense?
Also, I have no clue how to do (b) and (c)?

 

[Wesley Strik]

anyone?

 

[Wesley Strik]

Okay so I found an equation for the average energy of a plane wave:

<S>= E_m²/(2 c μ₀) where c is the speed of light, mu the magnetic permeability of free space, E_m=50 in this case. <S> is the averaged Poyting vector, such that ENERGY=<S> *area* time, which gives me, when I plug in the numbers: (area =3x2, t=30s)

for (b) I get: 0.597 kJ
for (c) I get: Cos[π/6] *0.859=0.517 kJ

*** I checked my B_m field of (a) by checking that E_m/B_m=c=3x10^8, which it did, so I assume I can divide by mu naught correctly