What is the equation for the bulk modulus of a Fermi gas?

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SUMMARY

The equation for the bulk modulus (B) of a Fermi gas is derived as B = -V(dp)/(dV) = (10U)/(9V) = (2nEf)/3, where U represents energy, V is volume, n is the number density, and Ef is the Fermi energy. The pressure (p) is expressed as p = (2U)/(3V), and the average energy is given by = (3Ef)/5. The derivation confirms that B can also be expressed as B = (2nEf)/5, highlighting a discrepancy in the textbook that may require further investigation.

PREREQUISITES
  • Understanding of thermodynamic concepts, specifically bulk modulus.
  • Familiarity with statistical mechanics and Fermi gas properties.
  • Knowledge of calculus, particularly differentiation and partial derivatives.
  • Basic understanding of quantum mechanics, including Fermi energy calculations.
NEXT STEPS
  • Study the derivation of the Fermi energy formula Ef = ((hbar)^2/(2*m))*(3*∏^2*N/V)^(2/3).
  • Learn about the implications of bulk modulus in different states of matter.
  • Explore the relationship between pressure, volume, and energy in statistical mechanics.
  • Investigate potential errors in textbooks regarding thermodynamic equations.
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Students and researchers in physics, particularly those focusing on statistical mechanics, thermodynamics, and quantum mechanics, will benefit from this discussion.

Jellybabe
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Homework Statement



It is just a line of equation from my Stat Mech textbook, that says

B = -V(dp)/(dV) = (10U)/(9V) = (2nEf)/3

where B is the bulk modulus, V is the volume, p is the pressure, U is the energy, n is the number per unit volume and Ef is the fermi energy.

Homework Equations



p = (2U)/(3V)
<E> = (3Ef)/5
U = N<E>
B = -V(dp)/(dV)

The Attempt at a Solution



I have found that p = (2nEf)/5 = (2NEf)/(5V) and verified that this is correct, so I get that the (partial) derivative wrt V is: -(2NEf)/(5V^2), then multiplying this by -V to get B = (2nEf)/5, which is a factor of 5/3 out.

Alternatively going from p = (2U)/(3V) and taking the derivative wrt V gives: -(2U)/(3V^2), multiplying this by -V then gives B = p = (2U)/(3V).

I don't know what I'm missing or whether it's a typo in the book.

Also apologies for the lack of LaTex, I haven't used it before and wasn't sure exactly how the equations were going to turn out.
 
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The energy at 0 K is U=3/5*N*Ef

Ef = ((hbar)^2/(2*m))*(3*∏^2*N/V)^(2/3), (hbar) is Planks constant in k space (h/2∏)
N=the number of orbitals electrons can occupy
m= mass of electron at rest
solve the equation Ef for V, (volume)

V=(3*∏^2*N)*(2*Ef*m/(hbar)^2)^(3/2)

plug U and V into the equation for the bulk modulous B=10U/9V and N, the term you don't know, drops out.
 

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