MHB What is the equation of a line passing through (6, -3) with a y-intercept of 8?

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To find the equation of a line passing through the point (6, -3) with a y-intercept of 8, first identify the slope using the two points: (6, -3) and (0, 8). The slope can be calculated as (8 - (-3)) / (0 - 6) = 11 / -6. Using the point-slope formula, the equation can be expressed as y - (-3) = (-11/6)(x - 6). Rearranging this into slope-intercept form gives the final equation as y = (-11/6)x + 8. The discussion emphasizes the importance of expressing the final answer in the correct slope-intercept format.
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Find an equation of the line passing through (6, -3) and has y-intercept 8. Express final answer in the form y = mx + b.

If it has y-intercept 8, this means the point (0, 8).

I now have 2 points.

1. Find the slope

2. Use the point-slope formula

3. Solve for y

Correct?
 
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A line passing through the point:

$$\left(x_1,y_1\right)$$

And having the $y$-intercept $b$, expressed in slope intercept form, will be:

$$y=\frac{y_1-b}{x_1}x+b$$
 
Is my information correct?
 
RTCNTC said:
Is my information correct?

Essentially, although I would change step 3 to read "Arrange in slope-intercept form." It's not enough to just solve for y, because we could have solved for y but not used the slope-intercept form, such as:

$$y=m(x-a)+b$$

We would want to arrange this as:

$$y=mx+(b-ma)$$
 
By solving for y I meant slope-intercept form y = mx + b.
 
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