Dirac
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vertex (-2, 3), focus (0,3)
Find the equation of the parabola.
Dirac.
Find the equation of the parabola.
Dirac.
The discussion revolves around finding the equation of a parabola given its vertex at (-2, 3) and focus at (0, 3). Participants are exploring the properties of parabolas and the relationship between the vertex, focus, and directrix.
The conversation includes various attempts to clarify the concepts involved in deriving the equation. Some participants express frustration with the pace of the discussion, while others emphasize the importance of understanding the underlying principles rather than simply obtaining the answer.
There are indications of differing expectations regarding the nature of assistance, with some participants seeking direct answers and others advocating for a focus on learning and understanding the process.
What have you tried so far?Dirac said:vertex (-2, 3), focus (0,3)
Find the equation of the parabola.
Dirac.
lurflurf said:What have you tried so far?
Find the directix. then recall
A parabola is the set of point equidistant from the focus and directix.
a will be the distance between the focus and vertex.Dirac said:So far I have got to this
((y-3)^2)=4a(x+2)
What now
Dirac.
lurflurf said:a will be the distance between the focus and vertex.
Why is this?
you started out withDirac said:How does one find the vertex
lurflurf said:you started out with
vertex (-2, 3), focus (0,3)
The points of a parabola are equidistant from it directrix and focus.
The vertex is the point closest to them. that is
distance(vertex,focus)<=distance(point on parabola,focus)
with equality only when the point is the vertex.
I already said you a is the distance betweenDirac said:Could you just post the answer, or would it get up your backside to post something useful in your life
Dirac.
Dirac said:Could you just post the answer, or would it get up your backside to post something useful in your life
Dirac.