What is the equation of motion for the mass in this system?

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Homework Help Overview

The discussion revolves around a mass-spring system involving a 0.1 kg mass connected to two springs with different spring constants (50 N/m and 30 N/m). The springs are initially loose and later fixed to walls, leading to a question about the lengths of the springs after stabilization. Participants are exploring the equations of motion and the effective spring constant of the system.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss different notations for the displacement of the mass and the implications of these choices on the equations derived. There is an exploration of the relationships between the spring forces and the distances involved, with some questioning the validity of their approaches.

Discussion Status

The conversation is ongoing, with participants providing insights into the equations and methods used. Some guidance has been offered regarding the interpretation of variables, but there remains a lack of consensus on the correct approach to derive the equation of motion and the effective spring constant.

Contextual Notes

There is a mention of potential confusion regarding the effective spring constant, with participants debating whether it should be considered as 30 or 80, depending on how the springs interact in the system.

Karol
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Homework Statement


A mass of 0.1 kg has 2 springs of length 20 cm attached to each side, like in the drawing. they are loose. one has a constant of 50 [N/m] and the other 30. The system is between 2 walls 10 cm distant from each spring.
At the second stage the springs are tied each to the nearest wall. the system stabilizes and the springs have different length. what is the length of each spring.
This is the first part of a question, but i got stuck.

Homework Equations


Spring force: $$F=kx$$

The Attempt at a Solution


At first i marked with x the distance the k=50 spring stretches. of course it is tied to the wall but i drew it apart in order to clarify. in this notation the k=30 spring stretches 0.1 meter + (0.1-x):
##50x=30\left[ 0.1+\left( 0.1-x \right) \right] \Rightarrow x=0.075##
And it is correct. but then i used an other notation, like in the second drawing, where x is the distance from the wall and tried:
##50(0.1-x)=30(0.1+x)##
And it's wrong, i can't understand why
 

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Karol said:

Homework Statement


A mass of 0.1 kg has 2 springs of length 20 cm attached to each side, like in the drawing. they are loose. one has a constant of 50 [N/m] and the other 30. The system is between 2 walls 10 cm distant from each spring.
At the second stage the springs are tied each to the nearest wall. the system stabilizes and the springs have different length. what is the length of each spring.
This is the first part of a question, but i got stuck.

Homework Equations


Spring force: $$F=kx$$

The Attempt at a Solution


At first i marked with x the distance the k=50 spring stretches. of course it is tied to the wall but i drew it apart in order to clarify. in this notation the k=30 spring stretches 0.1 meter + (0.1-x):
##50x=30\left[ 0.1+\left( 0.1-x \right) \right] \Rightarrow x=0.075##
And it is correct. but then i used an other notation, like in the second drawing, where x is the distance from the wall

x is the distance from the left wall to what? Your diagrams are not exactly clear.

and tried:
##50(0.1-x)=30(0.1+x)##
And it's wrong, i can't understand why

You will get that equation by taking x to be the displacement of the mass from its initial position, with positive x in the direction of the spring with constant 50 N/m.
 
It is best to solve problems symbolically, and to only plug in numbers at the very end. That way you can see at each step what is going on.

Try doing that with your second method.
 
pasmith said:
You will get that equation by taking x to be the displacement of the mass from its initial position, with positive x in the direction of the spring with constant 50 N/m.
Yes, this is another way to look at my second method. your x, the displacement of the mass, is equal to my x, the distance to the wall. of course the mass moves, but to me it was clearer to visualize with the mass fixed.
So, this equation:
##50(0.1-x)=30(0.1+x)##
Describes the mass's displacement x as you said but it's wrong.
 
Karol said:
Yes, this is another way to look at my second method. your x, the displacement of the mass, is equal to my x, the distance to the wall. of course the mass moves, but to me it was clearer to visualize with the mass fixed.
So, this equation:
##50(0.1-x)=30(0.1+x)##
Describes the mass's displacement x as you said but it's wrong.

Solving that gives 80x = 2, so x = 1/40 = 0.025. The extension in the spring with constant 50 is then 0.1 - x = 0.075, in agreement with your first method.
 
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Now continuing i have to show that the combined spring constant, or as the question says the effective force constant (i hope it's the same as i said) is 80.
But to my understanding it's 30 since one spring works against the other
 
Karol said:
Now continuing i have to show that the combined spring constant, or as the question says the effective force constant (i hope it's the same as i said) is 80.
But to my understanding it's 30 since one spring works against the other

Work out the equation of motion of the mass, and express it in the form <br /> m\ddot x = A - Bx.<br /> What is B?
 

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