What is the Equilibrium Angle of an Immersed Wooden Stick?

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SUMMARY

The equilibrium angle of a uniform wooden stick immersed in water is determined by the relationship between the densities of the stick and the water. When the stick is in equilibrium, the tangent of the angle θ is given by the formula tanθ = d/D, where d is the density of the wooden stick and D is the density of water. This conclusion is derived from the principles of buoyancy, which dictate that the buoyant force acts at the center of the rod. Therefore, the correct answer to the problem is option (b) d/D.

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nil1996
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Homework Statement


A uniform wooden stick of density d is completely immersed in water of density D (D>d). One end of the stick is free to rotate about a hinge which is attached to the wall of the container. In equilibrium the stick the stick makes an angle θ then tanθ is-
(a)0

(b)d/D

(c)1-d/D

(d)D/d

Homework Equations



related to buoyancy

The Attempt at a Solution


First of all i am not understanding the nature of buoyant force. In this case can we consider it to act at the middle of the rod?
 
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