What is the final velocity of a car with constant acceleration?

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Homework Help Overview

The problem involves a car with an initial velocity and constant acceleration, seeking to determine its final velocity after a specified time interval. The context is rooted in kinematics, specifically dealing with equations of motion under constant acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of an equation intended for distance rather than velocity, questioning the appropriateness of the equation used. Some express confusion about selecting the correct equation from those available for constant acceleration, noting the variables involved.

Discussion Status

The discussion is active, with participants providing feedback on the original poster's approach and suggesting a need to reconsider the equations being used. There is an emphasis on clarifying the relationship between the variables given in the problem and the equations of motion.

Contextual Notes

Participants note that the original poster may be misapplying an equation due to a misunderstanding of the variables involved and the specific requirements of the problem. There is also mention of the need to check units and ensure clarity in the problem statement.

subopolois
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Homework Statement


A speeding car has instantenous velocity of 1 m/s when a stopwatch reads 10 seconds. It has constant acceleration of 2 m/s^2.
What is the cars speed when it reaches the stopwatch reads 12 seconds.

Homework Equations


x= (Vinitial)(DeltaT) + 1/2(a09deltaT)^2
I think this is the right equation for constant acceleration...

The Attempt at a Solution


(1.0m/s)(2seconds) + 1/2(2m/s/s)(2)^2
2 + 4
= 6 m/s

This is a problem in my textbook, and the answer they give is 5 m/s. Am i using the wron equation? Or what am i doing wrong?
 
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You are using an equation to find a distance 'x', but you need a velocity.

Always check your units, e.g.:

The Attempt at a Solution


(1.0m/s)(2seconds) + 1/2(2m/s/s)(2)^2
2 + 4
= 6 m/s

Should be
(1 m/s)(2 seconds) + 1/2(2 m/s/s)(2 s)^2
2 m + 4 m
= 6 mThat's the distance traveled between 10 and 12 seconds, not what you are looking for... You need a different equation.
 
I'm stumped. Is it one of those other constant acceleration equations? Whenever I look at them, it always seems like I'm not looking at the right one because it has more variables than what I'm given in the question
 
subopolois said:
I'm stumped. Is it one of those other constant acceleration equations? Whenever I look at them, it always seems like I'm not looking at the right one because it has more variables than what I'm given in the question
Look at the problem statement.

You are given a time, an initial velocity, and an acceleration. You are asked to find the final velocity. Is there an equation which contains only those quantities?

==========================================================================================

To learn what the constant acceleration equations mean, you should write down each equation and write under it a list of each variable in that equation and what each variable stands for. You're not learning anything with your current approach, except how to guess (badly, unfortunately).
 

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