What is the final velocity of a tossed rock falling into a hole?

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SUMMARY

The final velocity of a rock tossed straight up and falling into a hole can be determined using kinematic equations. When the rock returns to its original launch height, its velocity equals the initial launch velocity but in the opposite direction. To calculate the final velocity as the rock hits the bottom of the hole, one must know the depth of the hole and apply the appropriate kinematic relation, such as \( v^2 = u^2 + 2as \), where \( v \) is the final velocity, \( u \) is the initial velocity, \( a \) is the acceleration due to gravity, and \( s \) is the depth of the hole.

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Homework Statement


A rock is tossed straight up with a velocity of When it returns, it falls into a hole deep.
What is the rock's velocity as it hits the bottom of the hole?


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The Attempt at a Solution

 
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What have you tried?
When the ball returns to it's original launch height it's velocity will be that with which it was launched with but in the opposite direction.
If you know the depth of the hole, you should then be able to compute the ball's final velocity using a kinematic relation.
 

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