What Is the Focal Length of the Lens When the Nickel's Image Doubles in Size?

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SUMMARY

The focal length of the lens is determined using the magnification formula M = h'/h = - (p/q) and the lens formula 1/f = 1/p + 1/q. Given that the image of the nickel is twice its size when the lens is positioned 2.90 cm from the nickel, the object distance (p) and image distance (q) can be calculated to find the focal length (f). The solution involves substituting the known values into the lens equation to derive the focal length definitively.

PREREQUISITES
  • Understanding of lens formulas, specifically 1/f = 1/p + 1/q
  • Knowledge of magnification concepts in optics
  • Familiarity with object distance (p) and image distance (q) definitions
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the derivation of the lens formula 1/f = 1/p + 1/q
  • Learn about different types of lenses and their properties
  • Explore practical applications of magnification in optical devices
  • Investigate how to calculate image distance (q) based on object distance (p) and magnification (M)
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding lens behavior and image formation in optical systems.

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Homework Statement


The nickel's image in the figure below has twice the diameter of the nickel when the lens is 2.90 cm from the nickel. Determine the focal length of the lens.


Homework Equations



M = h'/h = - (p/q)

The Attempt at a Solution


i don't really know how to start this one... eek
 
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There is a well-known equation for lenses, try that one.

Hint: it has a "1/f" in it.
 

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