What is the force exerted on the 7.7 kg block by the 10 kg block?

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SUMMARY

The discussion focuses on calculating the force exerted on a 7.7 kg block by a 10 kg block in a system where three blocks are pushed by a 91 N force across a rough surface with a coefficient of kinetic friction of 0.14. The relevant equations include F = ma and F = mg, which are essential for determining the acceleration of the blocks. Participants emphasize using these equations to derive the force interactions between the blocks. The solution involves calculating the acceleration and applying Newton's second law to find the force exerted on the 7.7 kg block.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of force, mass, and acceleration
  • Knowledge of kinetic friction and its calculation
  • Ability to apply basic algebra to solve equations
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  • Calculate the acceleration of the entire system using F = ma
  • Determine the net force acting on the 10 kg block
  • Apply F = ma to find the force exerted on the 7.7 kg block
  • Explore the effects of varying the coefficient of friction on the system's dynamics
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Homework Statement


Three blocks in contact with each other are pushed across a rough horizontal surface by a 91 N force. F---->[2kg] [7.7kg] [10kg]
If the coefficient of kinetic friction between each of the blocks and the surface is 0.14, find the magnitude of the force exerted on the 7.7 kg block by the 10 kg block.
Answer in units of N.

Homework Equations


F = ma
F = mg
a = F/M - ug

The Attempt at a Solution


from there, I found the acceleration but I am not sure how to find the force exerted on one block by another block.
 
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Welcome to PF!

Hi cmajor! Welcome to PF! :wink:
cmajor said:
… I found the acceleration but I am not sure how to find the force exerted on one block by another block.

Do F = ma on the 10 kg block …

what do you get? :smile:
 

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