What is the force exerted on the Deligne Dam by water pressure?

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The discussion focuses on calculating the force exerted on the Deligne Dam by water pressure, specifically using the curve defined by the equation y=0.7x² and the water level at 38 meters below the dam's top. The correct approach involves integrating the pressure over the dam's surface area, factoring in the water density of 1000 kg/m³ and gravitational acceleration of 9.8 m/s². Additionally, a related problem involves calculating the work required to empty a water-filled trough with a vertical cross-section shaped by the graph of y=x⁴, emphasizing the need for proper integral setup to determine the force and work accurately.

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(1 pt) The Deligne Dam on the Cayley River is built so that the wall facing the water is shaped like the region above the curve y=0.7 x^2 and below the line y= 300. (Here, distances are measured in meters.) The water level is 38 meters below the top of the dam. Find the force (in Newtons) exerted on the dam by water pressure. (Water has a density of 1000 kg/m^3, and the acceleration of gravity is 9.8 m/sec^2 .)

please help with this problem. I've been working on it every which way I can and my integrals STILL WRONG. URGH!

as well as this problem :
(1 pt) A trough is 7 feet long and 1 foot high. The vertical cross-section of the trough parallel to an end is shaped like the graph of y=x^{4} from x=-1 to x=1 . The trough is full of water. Find the amount of work in foot-pounds required to empty the trough by pumping the water over the top. Note: The weight of water is 62 pounds per cubic foot.

PLEASE PLEASE PLEASE. Thanks!
 
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(1000 * 9.8 ) * integral of (sqrt(y*4/0.7)(300-y)*dy) from 300 to 0 <--that is wrong...i also don't what to use as my d? for pdg
 

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