What is the force on the exerted edge of the cap

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Homework Help Overview

The problem involves calculating the force exerted on the edge of a bottle cap by a bottle opener when a force is applied to the opener. The context includes concepts of torque and lever arms in a physics setting.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between torque and force, with some attempting to calculate torque using different distances. Questions arise about how to correctly apply the concepts of torque in this scenario.

Discussion Status

Some participants have provided calculations and insights into the relationship between the forces and distances involved. There is an acknowledgment of confusion regarding the pivot point and how it affects the calculations. Clarifications have been offered, but no consensus has been reached on the final answer.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is also a noted misunderstanding regarding the pivot point in the torque calculations.

pauln
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Homework Statement


To remove a bottle cap, a student exerts a force of 40 N on the opener. What is the force on the exerted edge of the cap by the opener?

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Homework Equations



sigma(Tccw) = sigma(Tcw)
t=r*d

The Attempt at a Solution



t= 40*.35
t= 40*.30
+
= 26 n*m

i know its supposed to be in Newtons but I am not sure how to calculate force when torque is involved
 
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Since the torque is the same, force*dist is the same in both cases.
 
im still confused
i got torque for the whole bottle opener (t=40*.3) and i got torque for the opener coming in contact with the edge of the lid (t=40*.25)
the answer is 240 N but i come no where close to it :cry:
 
Torque of 40 N is acting at a dist of 30 cm from the point = torque of F acting at a dist of 5 cm from the pint =>
F*0.05 = 40*0.30 =>
F = 240. (in N)
 
argh i got it, I was thinking the start of the handle was a pivot so i was backwards in thinking for terms of distance
thanks for clearing it up :)
 

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