What is the force on the rider from the motorcycle?

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SUMMARY

The discussion centers on calculating the forces acting on a rider of a motorcycle accelerating up a ramp. The net force on the rider is determined using Newton's second law, yielding a value of 197.16 N when applying the formula F=ma with a mass of 63.6 kg and an acceleration of 3.1 m/s². The inquiry specifically addresses the distinction between the net force and the force exerted by the motorcycle on the rider, emphasizing the need to consider all forces acting on the rider to understand the total dynamics involved.

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  • Understanding of Newton's second law (F=ma)
  • Basic knowledge of forces and motion
  • Familiarity with inclined plane physics
  • Concept of net force and its components
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of forces acting on objects in motion, particularly in the context of inclined surfaces.

kittykatxox
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this is the problem:

A motorcycle and 63.6 kg rider accelerate at 3.1 m/s2 up a ramp inclined 9.1° above the horizontal. What are the magnitude of (a) the net force on the rider and (b) the force on the rider from the motorcycle?

I solved for a)

F=ma
= (63.6 kg)(3.1 m/s^2)
= 197.16 N

But I don't understand what b) means by the "force on the rider from the motorcycle"
 
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kittykatxox said:
But I don't understand what b) means by the "force on the rider from the motorcycle"
The force that the motorcycle exerts on the rider is just one force. What other forces act on the rider? (They all must add up to the net force, which you already calculated.)
 

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