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Tadhg

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So the big question, is the force that is applied to the ground to accelerate the bike the same as the force that is applied to the object that it impacts? I have tried to provide all the relevant data, but please ask if you need more.

Thank you.

1. Homework Statement

1. Homework Statement

A motorcycles engine provides a torque of 46.91 Nm the transmission multiples this torque to 1053.87 Nm. This torque applied to the ground through a wheel with an outer diameter of 0.72 m. The motorcycles front wheel hits an object at a distance of 1.3 m. Bike and rider mass=194.37 kg.Force = torque/distance

Force = 1053.87/(0.72/2)

Force applied to the ground to accelerate the motorcycle = 2924.97 N

Force=mass x acceleration

F=ma

a = 2924.97/194.37

a=15.05 m/s^2

Final Velocity^2 = Initial Velocity^2 + 2 x acceleration x distance

V^2=U^2+2as

V = squrt(0+2x15.05x1.3)

velocity = 6.14 m/s

Kinetic Energy = 1/2 x mass x velocity^2

Ek = 0.5 x 194.37 x 6.14^2

Kinetic Energy = 3664.67 Joules

Assuming no losses and that there is an instantaneous transfer of torque to the ground etc.