What Is the Formal Charge on P in PBr3 and N in NBrI2

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SUMMARY

The formal charge on phosphorus (P) in phosphorus tribromide (PBr3) and nitrogen (N) in nitrogen dibromoiodide (NBrI2) is calculated using the formula: Formal charge = number of valence electrons - number of non-bonded electrons - 1/2 number of bonding electrons. The correct formal charge for both P and N in their respective compounds is zero, contrary to the initial calculations of one. The error was due to a misinterpretation of the formula, specifically the term "number of electron pairs," which should be "number of non-bonded electrons."

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wahaj
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Homework Statement



find formal charge on P in PBr3 and N in NBrI2

Homework Equations



Formal charge = number of valence electrons-number of lone pairs- 1/2 number of bonding electrons

The Attempt at a Solution



FC on P = 5 - 1 - 3 = 1
FC on N = 5 - 1 - 3 = 1

these are wrong for some reason and I can't figure out. I know I have the lewis diagram correct for these molecules(I checked)
 
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How does the Lewis diagram help you here? I always calculated what I knew first and then balanced the molecule's charge by assigning the oxidation number of the unknown. In these examples, I would have assumed the halogens were -1 as you have and the P or N would have an equal but opposite charge.
 
NBrI2

Halides usually have charge of -1. The compound given is as neutral charge.
N, u
Br, -1
I, -1
I, -1
Total, 0.

Find u.
 
wahaj said:

Homework Statement



find formal charge on P in PBr3 and N in NBrI2

Homework Equations



Formal charge = number of valence electrons-number of electron pairs- 1/2 number of bonding electrons

The Attempt at a Solution



FC on P = 5 - 1 - 3 = 1
FC on N = 5 - 1 - 3 = 1

these are wrong for some reason and I can't figure out. I know I have the lewis diagram correct for these molecules(I checked)

The formal charges in both the cases is zero.
In your above formula for FC you wrote the second term as " number of electron pairs ",it should be " number of non-bonded electrons ".
 

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