ximath
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I am studying DC circuits and trying to derive formula for power; that is in fact
P = I.Vab
where Vab is the potential difference between two terminals of a circuit element.
From my previous studies, I know that.
P = dW / dt
I assume that for a small interval, dt, a single charge q has a small displacement , dx.
Then;
dW = E q dx
where E is magnitude of the electric field.
Hence, from the formula above,
P = E q dx / dt
This is all I could come up with. I want to go on with this idea to prove
P = I Vab
I know I need to substitute dq somewhere (to get I ) , somehow.. Simply replacing q with dq does not seem to work; it leads to an incorrect formula. (I find P = I dV ; I guess, if I do that.)
P = I.Vab
where Vab is the potential difference between two terminals of a circuit element.
From my previous studies, I know that.
P = dW / dt
I assume that for a small interval, dt, a single charge q has a small displacement , dx.
Then;
dW = E q dx
where E is magnitude of the electric field.
Hence, from the formula above,
P = E q dx / dt
This is all I could come up with. I want to go on with this idea to prove
P = I Vab
I know I need to substitute dq somewhere (to get I ) , somehow.. Simply replacing q with dq does not seem to work; it leads to an incorrect formula. (I find P = I dV ; I guess, if I do that.)