What is the formula for electrical power in a DC circuit?

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SUMMARY

The formula for electrical power in a DC circuit is defined as P = I.Vab, where Vab represents the potential difference between two terminals of a circuit element. The derivation begins with the relationship P = dW/dt, where dW is the work done by a charge q moving through an electric field E over a distance dx. To accurately derive the power formula, one must consider a differential charge dq and its movement, which aligns with the principles of Ohm's law. This approach emphasizes the aggregate behavior of multiple charges rather than focusing on a single charge.

PREREQUISITES
  • Understanding of DC circuit fundamentals
  • Familiarity with Ohm's Law
  • Knowledge of electric fields and work-energy principles
  • Basic calculus concepts, particularly differentiation
NEXT STEPS
  • Study the derivation of Ohm's Law in detail
  • Learn about the relationship between electric field and potential difference
  • Explore the concept of differential calculus in physics applications
  • Review the Wikipedia page on Ohm's Law for additional insights
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Students studying electrical engineering, physics enthusiasts, and anyone seeking to understand the principles of power in DC circuits.

ximath
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I am studying DC circuits and trying to derive formula for power; that is in fact
P = I.Vab

where Vab is the potential difference between two terminals of a circuit element.

From my previous studies, I know that.

P = dW / dt

I assume that for a small interval, dt, a single charge q has a small displacement , dx.

Then;

dW = E q dx

where E is magnitude of the electric field.

Hence, from the formula above,

P = E q dx / dt

This is all I could come up with. I want to go on with this idea to prove

P = I Vab


I know I need to substitute dq somewhere (to get I ) , somehow.. Simply replacing q with dq does not seem to work; it leads to an incorrect formula. (I find P = I dV ; I guess, if I do that.)
 
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ximath said:
...I assume that for a small interval, dt, a single charge q has a small displacement , dx.

Then;

dW = E q dx

where E is magnitude of the electric field.

It would be more advantageous to assume that you have a differential charge dq moving a distance x in the electric field E. (And does dq/dt ring a bell?) Also I believe this approach is more correct, since you have numerous charges (instead of a single one) and you're attempting to find their aggregate behaviour when you use Ohm's law.

This derivation is also a very macroscopic one; the standard first-principles approach is given at Wikipedia:
http://en.wikipedia.org/wiki/Ohm's_law
 

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