What is the formula for the radius of a satellite's orbit?

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Homework Help Overview

The discussion revolves around calculating the radius of a satellite's orbit based on the gravitational force it experiences. The problem involves gravitational equations and concepts related to circular motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the gravitational force acting on the satellite and its relationship to the radius of orbit. There are attempts to apply relevant formulas, and questions arise regarding the correctness of the formulas used and the calculations performed.

Discussion Status

Some participants have provided guidance on the appropriate formulas to use, while others express uncertainty about their calculations and seek further clarification. Multiple interpretations of the problem and its solution are being explored.

Contextual Notes

There is mention of rounding errors affecting the final answer, and some participants question the assumptions made in their calculations. The original poster expresses confusion about the formulas and seeks additional opinions.

jacob117
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Homework Statement


A 129 kg satellite experiences a gravitational force by the Earth of 790 N. What is the radius of the satellite's orbit?


Homework Equations


F=GM/R^2


The Attempt at a Solution

 
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For an object of mass m under the effect of Earth's gravitational pull, the force pulling it towards the center of the Earth is of a magnitude:

|Fgravity| = m((GMearth)/r²)
where r is the distance of the object from the center of the earth.

Another formula you'll find helpful if there are any follow-up questions is the following:
An object in simple circular motion around a fixed point, is being pulled towards the center of its orbit by a force of magnitude:
|Fcentripetal| = mv²/r
Where v is the tangential speed of the object, and r is the radius of its circular orbit.

Please make an attempt at the solution before asking us to help.
 
Last edited:
r^2=G(m1m2)/F
r^2=6.67x10^-11(129x5.98x10^24)/790
r^2=6.67x10^-11(7.7142x10^26)/790
r^2=6.67x10^-11(9.764810127x10^23)
r^2=6.513128355x10^13
r=8070395.501

thats the answer i got but it is still wrong...i need some serious help...
 
Final answer is 8068.29466 kilometers, according to Google calculator, so you're in the ball-park. Rounding errors could account for the difference in our answers.
Why do think you're wrong?
 
so did i use the proper formula?
 
Yes, I think so. But can you explain to me why that was the proper formula?
 
hey guys i need some more opinions on this problem...and i just took a guess at the formula...
 
jacob117 said:
hey guys i need some more opinions on this problem...and i just took a guess at the formula...

Why do you need more opinions? You got the right answer.

As for why the formula is right, F=Gm1m2/r^2 is Newton's law of gravitation, relating gravitational force to mass and distance. You know F; that was given in the question. You know m1 and m2; one is the mass of the Earth and the other is the astronaut's mass. G is a constant. With one equation and one unknown (r), you can solve for r, which is what the question asks for.
 
jacob117 said:
hey guys i need some more opinions on this problem...and i just took a guess at the formula...

Not to sound nitpicky, but RoyalCat gave you the correct formula in Post #2. Your formula in Post #1 was wrong.
 

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