What is the Free Body Diagram for a Chain with Four Links?

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To draw the free body diagram (FBD) for a chain with four links, focus on the forces acting on each link. The first link experiences tension from the rope, its weight, and a normal force from the second link. It is unnecessary to consider the influence of links beyond link two on link one, as their effects are transmitted through link two. Each link is primarily influenced by two normal forces from adjacent links and gravity. This understanding simplifies the analysis of the system's dynamics.
jhson114
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hello. I need help drawing free body diagram for four links on a chain. The picture looks like this:

| <-thats a rope
8 <-these are links; they should all be connected
8

heres a good picture of a chain:
http://homepage.mac.com/kpreid/povray/chain.png

the first link is connected by a rope, and i need to draw FBD for each links.
For the first link, i have Tension force from the rope, Weight force, and Normal force from link two. Is this correct? how would you show all other weights pulling link 1 beyond the link 2? and is it even correct to call the force link two is applying to link 1 a normal force?
help please. thank you
 
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help please T.T
 
free body diagram

Each link of the rope is uder the influence of just three forces. Two normal forces - from the top link and the bottom link and one of gravity.

You need not consider the influence that links other than link 2 are applying on link 1. Because if there is such an influence, it is just through link 2 and no other direct influence.

rest is correct

spacetime
www.geocities.com/physics_all/index.html
 
thanks a lot for the help :)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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