What is the Frequency of Oscillation for a Gibbon Hanging on a Tree Branch?

Click For Summary
SUMMARY

The frequency of oscillation for a gibbon hanging on a tree branch can be estimated using the formula for a physical pendulum. Given the center of mass at 0.481 m from the branch and a rotational inertia divided by mass of I/m = 0.256 m², the frequency can be calculated using the formula f = (1/2π) * √(m*g/I), where g is the acceleration due to gravity. This results in a specific frequency value that reflects the gibbon's swinging motion.

PREREQUISITES
  • Understanding of physical pendulum dynamics
  • Knowledge of rotational inertia concepts
  • Familiarity with basic physics equations involving frequency and oscillation
  • Ability to perform calculations involving gravitational acceleration
NEXT STEPS
  • Research the derivation of the physical pendulum frequency formula
  • Learn about the effects of mass distribution on oscillation frequency
  • Explore examples of oscillation in biological systems
  • Study the impact of amplitude on frequency in small oscillations
USEFUL FOR

Physics students, biomechanics researchers, and anyone interested in the dynamics of swinging motions in biological organisms.

gillammd
Messages
1
Reaction score
0
A gibbon, hanging onto a horizontal tree branch with one arm, swings with a small amplitude. The gibbon's center of mass is 0.481 m from the branch and its rotational inertia divided by its mass is I/m = 0.256 m2. Estimate the frequency of oscillation.
 
Physics news on Phys.org
Have you tried solving the problem yet? We need to know where you are having difficulty before trying to help. In other words: Show us your work.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
6K
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
3
Views
858
Replies
7
Views
3K
Replies
9
Views
2K
Replies
17
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
6K
Replies
4
Views
1K