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Frequency of Oscillation of a monkey hanging from a tree

  1. Oct 28, 2009 #1
    1. The problem statement, all variables and given/known data

    A gibbon, hanging onto a horizontal tree branch with one arm, swings with a small amplitude. The gibbon's center of mass is 0.410 m from the branch and its rotational inertia divided by its mass is I/m = 0.289 m2. Estimate the frequency of oscillation.


    2. Relevant equations

    d = 1/2L
    T = 2π * SQRT(I/mgd)
    f = 1/T

    3. The attempt at a solution

    Okay, they have given me I/m, and I need to find f using the last equation. In order to find T, I need to use the first and second equation.

    d = 1/2(.410)
    d = .205

    I/m = .289 m2

    T = 2π * SQRT([.289][9.8][.205])
    T = 2π * .762
    T = 4.78

    f = 1/4.78
    f = .209 Hz

    Which is, of course, wrong. I'm thinking I'm getting confused by the I/m = 0.289 m2 value which is throwing off how I plug and chug. I may even have the wrong equation. Thanks for all your help.
     
  2. jcsd
  3. Oct 28, 2009 #2
    Nevermind, I solved it!
     
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