What is the Frequency of the Third Harmonic in a Heated, Stretched Yarn?

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Homework Help Overview

The problem involves determining the frequency of the third harmonic of a heated, stretched yarn, considering factors such as the yarn's length, mass, elastic constant, and the linear expansion of a metal bar affecting the tension in the yarn.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the linear expansion of the metal bar and the resulting tension in the yarn. There are attempts to derive the frequency of the third harmonic based on the provided parameters, but some participants express uncertainty about the correctness of the formulas used.

Discussion Status

There is ongoing exploration of the problem, with participants questioning the assumptions made regarding the coefficients of linear expansion and the derivation of the frequency formula. Some guidance has been offered regarding the integration of the linear expansion function, but no consensus has been reached on the correct approach.

Contextual Notes

Participants note that the coefficient of linear expansion varies with temperature, which may affect the calculations. There is also mention of confusion between harmonics and overtones, indicating a need for clarity in terminology.

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Homework Statement


A yarn of material that cannot dilate, length L, mass m and elastic constant K is trapped and stretched with negligible tension between the two supports A and B attached to the ends of the metal bar, CD, whose coefficient of expansion varies linearly from to , increasingly with temperature in the range of interest of the question. Determine the frequency of the third harmonic that is established in the rope when heated ΔT.


The Attempt at a Solution



\alpha _{eq} = \dfrac{\alpha 1 + \alpha 2}{2}

Since the metal bar expands, separation between A and B increases. This creates a tension in the string. The change in length is given by LαΔT.
F = KLαΔT
Frequency of third harmonic = 4v/2L
where v=\sqrt{\dfrac{FL}{m}}

If I substitute the value of F, the answer comes out to be wrong.
 
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utkarshakash said:
...linearly from to , increasingly ...

Something seems to be missing here.

The Attempt at a Solution



\alpha _{eq} = \dfrac{\alpha 1 + \alpha 2}{2}
[STRIKE]I am not sure but I think this is incorrect. The question says that coefficient of linear expansion varies linearly with temperature so I think you should find it as a function of temperature and then obtain the change in length through integration.[/STRIKE]

EDIT: Sorry, that is correct, integration yields the same result. So the only possible error is in your formula for frequency of third harmonic.
 
Last edited:
Pranav-Arora said:
Something seems to be missing here.


[STRIKE]I am not sure but I think this is incorrect. The question says that coefficient of linear expansion varies linearly with temperature so I think you should find it as a function of temperature and then obtain the change in length through integration.[/STRIKE]

EDIT: Sorry, that is correct, integration yields the same result. So the only possible error is in your formula for frequency of third harmonic.

Ah! That was a silly mistake. I confused "harmonics" with "overtones". Thanks for pointing out.
 
Here's the correct answer

\dfrac{3}{2} \sqrt{\dfrac{K Δ T (\alpha_1 + \alpha_2)}{2m}}
 
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