What is the gravitational force homework

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SUMMARY

The gravitational force exerted by a solid sphere of uniform density with a mass of 3.0×104 kg and a radius of 1.0 m on a 1.0 kg particle located 0.50 m from its center is calculated using the formula F = M1*M2*G / r2. However, since the particle is located inside the sphere, the gravitational force is not simply proportional to 1/r2. Instead, only the mass of the sphere beneath the particle contributes to the gravitational attraction, as per Gauss' Law, which states that the gravitational field inside a uniform shell is zero.

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  • Understanding of gravitational force calculations
  • Familiarity with Gauss' Law
  • Knowledge of solid sphere properties
  • Basic algebra for manipulating equations
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  • Study Gauss' Law and its applications in gravitational fields
  • Learn about gravitational force calculations for objects inside solid spheres
  • Explore the concept of gravitational fields and potential
  • Review the principles of uniform density in physics
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Homework Statement



A solid sphere of uniform density has a mass of 3.0×10^4 kg and a radius of 1.0 m. What is the gravitational force due to the sphere on a particle of mass 1.0 kg located at a distance of 0.50 m from the center of the sphere?

Homework Equations



F = M1*M2*G / r^2

The Attempt at a Solution



F = (1*3E4*6.67E-11) / (0.5)^2

F = 8.00E-6 NAm I doing something wrong because the question is asking for the force of a particle inside the sphere?
 
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Yes, the gravitational field inside a solid sphere is not simply proportional to 1/r^2.
Do you know Gauss' Law?
 


The gravity inside a shell of uniform mass density will be 0.

So what you are interested in is how much mass remains in the sphere beneath you.

To calculate the effect of gravity at half the radius then you are only worried about the mass of attraction from a sphere of half the radius (since that's below the point of interest, with what is above having no effect).
 

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