What is the growth rate of a differentiable function?

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Discussion Overview

The discussion revolves around the concept of growth rates of differentiable functions, particularly focusing on how to define and calculate the growth rate in various contexts. Participants explore different formulas for growth rates, including continuous and constant growth rates, and relate these to real-world examples such as population growth.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants propose that the growth rate can be expressed as $$w_u(t)=\frac{d(\ln u(t))}{dt}$$ and question how this relates to other definitions of growth rate.
  • Others suggest that the growth rate might be defined as $$w(t)=\frac{u(t)-u(0)}{u(0)}$$, indicating uncertainty about the correct formula.
  • A participant notes that the definition of growth rate can vary depending on the context, such as population growth versus business applications.
  • One participant provides a detailed example of calculating growth rate using population data, illustrating the concept of growth fraction and its relation to time.
  • There is a discussion about whether the continuous growth rate is equivalent to the slope of the function's graph, with differing opinions on this point.
  • Another participant clarifies that the growth rate is the proportional increase per unit of time, which differs from the slope of the graph.
  • Some participants mention that the growth rate can also be interpreted as the slope of the graph of $$\ln u$$, reinforcing the connection between logarithmic differentiation and growth rates.

Areas of Agreement / Disagreement

Participants express multiple competing views regarding the definition and calculation of growth rates, and the discussion remains unresolved with no consensus reached on a single definition.

Contextual Notes

Limitations include varying definitions of growth rate depending on context, and the discussion does not resolve the differences in interpretation or application of the formulas presented.

mathmari
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Hey! :o

We have that the differentiable function $u(t)$ is stricly positiv for all $t\in [0,\infty)$ and that $w$ is the continuous growth rate of $u(t)$.
I want to show that $$w_u(t)=\frac{d(\ln u(t))}{dt}$$How is the formula for the growth rate? Is it maybe given by $w(t)=\frac{u(t)-u(0)}{u(0)}$ ? (Wondering)
 
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mathmari said:
Hey! :o

We have that the differentiable function $u(t)$ is stricly positiv for all $t\in [0,\infty)$ and that $w$ is the constant growth rate of $u(t)$.
I want to show that $$w_u(t)=\frac{d(\ln u(t))}{dt}$$How is the formula for the growth rate? Is it maybe given by $w(t)=\frac{u(t)-u(0)}{u(0)}$ ? (Wondering)

Hey mathmari! (Smile)

That depends on the definition of growth rate, which depends on the area of expertise that it applies to.
For instance the population growth rate is the percentage growth of a population per unit of time, while in business the compound annual growth rate is the geometric progression ratio that provides a constant rate of return over the time period.

Which "growth rate" are we talking about? (Wondering)

EDIT: Actually, they are probably the same thing. I think it's the growth fraction per unit of time.
$$\text{Growth rate} = \frac {\frac{\Delta u}{u}}{\Delta t} = \frac {\frac{\Delta u}{\Delta t}}{u} = \frac{u'(t)}{u(t)}$$
(Thinking)
 
I like Serena said:
Actually, they are probably the same thing. I think it's the growth fraction per unit of time.
$$\text{Growth rate} = \frac {\frac{\Delta u}{u}}{\Delta t} = \frac {\frac{\Delta u}{\Delta t}}{u} = \frac{u'(t)}{u(t)}$$
(Thinking)

How do we get the formula $\text{Growth rate} = \frac {\frac{\Delta u}{u}}{\Delta t} $ and especially the numerator? I got stuck right now... (Wondering)
P.S. I changed at my first post the "constant growth rate" to "continuous growth rate".
 
Last edited by a moderator:
Suppose we start with a population $u$ of 100 and 2 days later the population is 110.

Then the population increase $\Delta u$ is:
$$\Delta u=10$$
in those 2 days.

The growth fraction or growth proportion is the increase in population divided by the population size:
$$\text{Growth fraction} = \frac{\Delta u}{u} = \frac{10}{100} = 0.1 = 10\%$$

And the growth rate is the growth fraction per unit of time:
$$\text{Growth rate} = \frac{\text{Growth fraction}}{\Delta t} = \frac{10\%}{2 \text{ days}} = 5\frac{\%}{\text{day}} = 0.05 \text{ day}^{-1}$$

In other words, the formula for growth rate is:
$$\text{Growth rate} = \frac{\frac{\Delta u}{u}}{\Delta t}$$

This growth rate can change continuously from one time to another.
To get an accurate and stable number, we take the limit $\Delta t \to 0$ to get:
$$\text{Growth rate} = \lim_{\Delta t \to 0} \frac{\frac{\Delta u}{u}}{\Delta t} = \frac 1u \lim_{\Delta t \to 0} \frac{\Delta u}{\Delta t} = \frac{u'}{u}$$
(Thinking)
 
Ah ok! (Nerd)

Is the continuous growth rate of a function the slope of its graph? (Wondering)
 
mathmari said:
Is the continuous growth rate of a function the slope of its graph? (Wondering)

Nope.
The slope of the graph is the increase per unit of time.
The growth rate is the proportional increase per unit of time - it's the slope divided by the function value. (Nerd)
 
Alternatively, it's the slope of the graph of $\ln u$, since we have:
$$\text{Growth rate} = \d{(\ln u)}{t} = \frac{u'}{u}$$
(Thinking)
 
I like Serena said:
Alternatively, it's the slope of the graph of $\ln u$, since we have:
$$\text{Growth rate} = \d{(\ln u)}{t} = \frac{u'}{u}$$
(Thinking)

Ah ok... I see! (Smile)

Thank you very much! (Mmm)
 

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