MHB What is the growth rate of a differentiable function?

mathmari
Gold Member
MHB
Messages
4,984
Reaction score
7
Hey! :o

We have that the differentiable function $u(t)$ is stricly positiv for all $t\in [0,\infty)$ and that $w$ is the continuous growth rate of $u(t)$.
I want to show that $$w_u(t)=\frac{d(\ln u(t))}{dt}$$How is the formula for the growth rate? Is it maybe given by $w(t)=\frac{u(t)-u(0)}{u(0)}$ ? (Wondering)
 
Last edited by a moderator:
Physics news on Phys.org
mathmari said:
Hey! :o

We have that the differentiable function $u(t)$ is stricly positiv for all $t\in [0,\infty)$ and that $w$ is the constant growth rate of $u(t)$.
I want to show that $$w_u(t)=\frac{d(\ln u(t))}{dt}$$How is the formula for the growth rate? Is it maybe given by $w(t)=\frac{u(t)-u(0)}{u(0)}$ ? (Wondering)

Hey mathmari! (Smile)

That depends on the definition of growth rate, which depends on the area of expertise that it applies to.
For instance the population growth rate is the percentage growth of a population per unit of time, while in business the compound annual growth rate is the geometric progression ratio that provides a constant rate of return over the time period.

Which "growth rate" are we talking about? (Wondering)

EDIT: Actually, they are probably the same thing. I think it's the growth fraction per unit of time.
$$\text{Growth rate} = \frac {\frac{\Delta u}{u}}{\Delta t} = \frac {\frac{\Delta u}{\Delta t}}{u} = \frac{u'(t)}{u(t)}$$
(Thinking)
 
I like Serena said:
Actually, they are probably the same thing. I think it's the growth fraction per unit of time.
$$\text{Growth rate} = \frac {\frac{\Delta u}{u}}{\Delta t} = \frac {\frac{\Delta u}{\Delta t}}{u} = \frac{u'(t)}{u(t)}$$
(Thinking)

How do we get the formula $\text{Growth rate} = \frac {\frac{\Delta u}{u}}{\Delta t} $ and especially the numerator? I got stuck right now... (Wondering)
P.S. I changed at my first post the "constant growth rate" to "continuous growth rate".
 
Last edited by a moderator:
Suppose we start with a population $u$ of 100 and 2 days later the population is 110.

Then the population increase $\Delta u$ is:
$$\Delta u=10$$
in those 2 days.

The growth fraction or growth proportion is the increase in population divided by the population size:
$$\text{Growth fraction} = \frac{\Delta u}{u} = \frac{10}{100} = 0.1 = 10\%$$

And the growth rate is the growth fraction per unit of time:
$$\text{Growth rate} = \frac{\text{Growth fraction}}{\Delta t} = \frac{10\%}{2 \text{ days}} = 5\frac{\%}{\text{day}} = 0.05 \text{ day}^{-1}$$

In other words, the formula for growth rate is:
$$\text{Growth rate} = \frac{\frac{\Delta u}{u}}{\Delta t}$$

This growth rate can change continuously from one time to another.
To get an accurate and stable number, we take the limit $\Delta t \to 0$ to get:
$$\text{Growth rate} = \lim_{\Delta t \to 0} \frac{\frac{\Delta u}{u}}{\Delta t} = \frac 1u \lim_{\Delta t \to 0} \frac{\Delta u}{\Delta t} = \frac{u'}{u}$$
(Thinking)
 
Ah ok! (Nerd)

Is the continuous growth rate of a function the slope of its graph? (Wondering)
 
mathmari said:
Is the continuous growth rate of a function the slope of its graph? (Wondering)

Nope.
The slope of the graph is the increase per unit of time.
The growth rate is the proportional increase per unit of time - it's the slope divided by the function value. (Nerd)
 
Alternatively, it's the slope of the graph of $\ln u$, since we have:
$$\text{Growth rate} = \d{(\ln u)}{t} = \frac{u'}{u}$$
(Thinking)
 
I like Serena said:
Alternatively, it's the slope of the graph of $\ln u$, since we have:
$$\text{Growth rate} = \d{(\ln u)}{t} = \frac{u'}{u}$$
(Thinking)

Ah ok... I see! (Smile)

Thank you very much! (Mmm)
 

Similar threads

Back
Top