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What is the heat removal in J/min

  1. Dec 6, 2017 #1
    1. The problem statement, all variables and given/known data
    What is H, the rate of heat absorbtion by an air conditioner with an EER of 8.3 that operates at 1800 W? Recall that 1Btu=1055J. Express your answer in joules per minute.

    2. Relevant equations
    H/P=EER

    3. The attempt at a solution
    H=EER*P
    H=(8.3 BTU/HR/W)*(1800 W)
    H=(14,940 BTU / hr)*(1055 J / 1 BTU)*(1 hr / 60 min) = 262,695 J/min
    This is wrong and I am not sure why. I thought maybe I was using the wrong number of sig figs, so I tried 260,000 J/min and 263,000 J/min. Anybody that can help me see what I am doing wrong, I would very much appreciate it.
    Thank you
    Chad
     
  2. jcsd
  3. Dec 6, 2017 #2

    BvU

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    Perhaps leave out the comma ? I get same as you ...
     
  4. Dec 6, 2017 #3
    I put the comma in for clarity when I posted to the forum. I didn't use one when I input the answer. I just thought maybe I missed something but it doesn't sound like I did. Thank you
     
  5. Dec 6, 2017 #4
    The answer was correct, but for some reason it wanted it in scientific notation. 2.63*105 It has never mattered before if it was scientific or regular, it must just have been a fluke. Thank you
     
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