Heat Pump Problem: Max Heat Transfer/COP Calculation

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Homework Help Overview

The discussion revolves around calculating the coefficient of performance (COP) of an ideal heat pump and determining the maximum heat it can deliver based on given temperatures and electrical power input. The subject area includes thermodynamics and heat transfer principles.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of COP using temperature conversions and question the use of different constants for temperature in Kelvin. There is also a focus on the significance of rounding during calculations and its impact on the final answer.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the calculations and addressing discrepancies in significant figures. Some guidance has been offered regarding rounding practices and temperature conversions, but no consensus has been reached on the final numerical answers.

Contextual Notes

Participants note the importance of using the correct conversion from Celsius to Kelvin, highlighting a common misunderstanding regarding the constants used in calculations. There is also mention of homework constraints regarding significant figures.

toothpaste666
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Homework Statement


A)What is the coefficient of performance of an ideal heat pump that extracts heat from 11∘C air outside and deposits heat inside your house at 30∘C?
B) If this heat pump operates on 2000W of electrical power, what is the maximum heat it can deliver into your house each hour?

Homework Equations


COP = QH/W
COPideal = TH/(TH-TL)

The Attempt at a Solution


TH = 30 + 270 = 300
TL = 11 + 270 = 281

COPideal = 300/(300-281) = 16
that part came up right
for the second part
W = 2000 J/s

COP = QH/W
QH = COP(W) = 16 (2000 J/s) = 32000 J/s
32000 J/s (3600 s/ h) = 115200000 J/h
i rounded to 2 sig figs because that's what the question wanted but it was wrong. What mistake did I make?
 
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toothpaste666 said:

Homework Statement


A)What is the coefficient of performance of an ideal heat pump that extracts heat from 11∘C air outside and deposits heat inside your house at 30∘C?
B) If this heat pump operates on 2000W of electrical power, what is the maximum heat it can deliver into your house each hour?

Homework Equations



The Attempt at a Solution


TH = 30 + 270 = 300
TL = 11 + 270 = 281
why are you using oK = oC + 270 when it's oK = oC + 273?
Even though to 2 sig. digits it worked out OK. I would still round off at the end of calculations rather than in the middle somewhere.
I suppose to 2 sig. digits the answer is 1.2e8 J.

Otherwise I see nothing wrong with what you did.
 
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Thanks! it wouldn't take 1.2e8 so i tried 1.1e8 and it took that for some reason
 
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toothpaste666 said:
Thanks! it wouldn't take 1.2e8 so i tried 1.1e8 and it took that for some reason
1.1e8 is a truncation. 1.2e8 is the correct answer to 2 significant digits. Complain! :smile:
 
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worth a shot. thanks!
 
toothpaste666 said:
worth a shot. thanks!
Oops, don't complain yet! Redoing the numbers, it's 1.1e8 after all:
COP = 303/19 = 15.947
W = 15.947 x 2000 x 3600 = 1.148e8 which to 2 sig # is 1.1e8.
(Although I suppose you could argue 1.148 ~ 1.15 which to 2 sig digits is 1.2.)

Again, note that K = oC + 273.15 or 273 for short. Don't use 270 ever.
 
ahh yea i got to get out of the habit of rounding too soon. This one is very close
 
rude man said:
1.1e8 is a truncation. 1.2e8 is the correct answer to 2 significant digits. Complain! :)
Hmm.. I get ((30+273)/(30-11))*2000*3600=1.148...e8
 
haruspex said:
Hmm.. I get ((30+273)/(30-11))*2000*3600=1.148...e8
Please see my post #6. I believe we have concordance.
 

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